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  • $\begingroup$ This is originally how I thought of it +1. But I found it a little bit unconvincing for some reason. $\endgroup$ Commented Nov 11, 2014 at 19:31
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    $\begingroup$ @d'alar'cop I find it very convincing. The first extraction has no effect on the second, other than the fact that it leaves one less red ball in the heap. $\endgroup$ Commented Nov 11, 2014 at 19:36
  • $\begingroup$ I understand the reasoning and I think it's true as well, but I find the accepted version more "complete" (I guess that's why I feel a little more convinced by it). $\endgroup$ Commented Nov 11, 2014 at 19:47
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    $\begingroup$ @d'alar'cop You're right, that looks like the proper way of computing the odds. I consider this to be a shortcut towards the answer and found it interesting enough to post. $\endgroup$ Commented Nov 11, 2014 at 19:51