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Puzzling

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15
  • $\begingroup$ You mean the number of each piece may not be more than sum of the numbers of pieces of other two ?(rule #2) $\endgroup$ Commented Nov 25, 2017 at 12:17
  • $\begingroup$ Sorry, english is not my first language. I mean if you have 3 copies of two pieces, you can have 2, 3, or 4 of the other piece. Maybe you can help me phrase that a bit better. The difference between number of rooks and number of bishops may only be 0 or 1. Same for the other two combination of pieces. $\endgroup$ Commented Nov 25, 2017 at 12:27
  • $\begingroup$ Maybe: The number of each piece must be within 1 of the number of pieces of each of the other two. $\endgroup$ Commented Nov 25, 2017 at 14:48
  • $\begingroup$ So if I get this correctly... If I have 2 knights and 3 bishops, I can have 6 rooks? $\endgroup$ Commented Nov 25, 2017 at 15:08
  • 1
    $\begingroup$ The usual assumption in this kind of problems is that all the pieces are the same colour, but can still attack each other. Does this hold here? $\endgroup$ Commented Nov 26, 2017 at 11:27