Timeline for Beating a DC using a pool of polyhedral dice while maximizing the sum of remaining dice
Current License: CC BY-SA 4.0
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14 events
| when toggle format | what | by | license | comment | |
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| Jan 4, 2025 at 23:55 | history | edited | HighDiceRoller |
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| Oct 29, 2024 at 9:53 | comment | added | Em Harung | @HighDiceRoller Thanks! | |
| Oct 29, 2024 at 9:52 | vote | accept | Em Harung | ||
| Oct 29, 2024 at 9:41 | comment | added | Em Harung | Sorry for beeing unclear - the assumption by Dale M and eddymage was correct, I edited it for clarity's sake. | |
| Oct 29, 2024 at 9:33 | history | edited | Em Harung | CC BY-SA 4.0 |
added 7 characters in body
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| Oct 29, 2024 at 6:11 | comment | added | Eddymage | @HighDiceRoller I think that they mean that for just maximizing the sum of the remaining dice you should choose 4 and 6, but these do not overcome the DC of 12. | |
| Oct 29, 2024 at 5:12 | review | Close votes | |||
| Oct 29, 2024 at 14:04 | |||||
| Oct 29, 2024 at 5:09 | answer | added | HighDiceRoller | timeline score: 1 | |
| Oct 29, 2024 at 4:57 | comment | added | Dale M | @HighDiceRoller I think they are trying to maximise the value of dice left over. Voting to close until they clarify. | |
| Oct 29, 2024 at 3:40 | comment | added | HighDiceRoller | 6 + 4 doesn't meet the DC, do you mean to have a DC of 10? | |
| Oct 29, 2024 at 0:42 | history | edited | Em Harung | CC BY-SA 4.0 |
deleted 15 characters in body
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| Oct 29, 2024 at 0:20 | history | edited | Thomas Markov | CC BY-SA 4.0 |
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| S Oct 29, 2024 at 0:00 | review | First questions | |||
| Oct 29, 2024 at 0:44 | |||||
| S Oct 29, 2024 at 0:00 | history | asked | Em Harung | CC BY-SA 4.0 |