Is the gravity pull of the Earth negligible at 50 miles up...
No it's almost the same. Gravitational acceleration varies as
$$a = \frac{GM_{Earth}}{r^2}$$
Let's call 50 miles 80 km. Earth's equatorial radius is about 6378 km, so gravity at 80 km is
$$\left(\frac{6378}{6378+80}\right)^2 \approx 97.5\text{% of Earth.}$$
...or is the weightlessness experience just relative to a falling airframe?
You guessed it!You guessed it! They both just rise and fall at the same rate, so the "weightlessness experience" is just that, an experience no different than jumping off of a stool, except that it's longer because they jumped higher.
I'll add a link to Q&A here that address this in greater detail, and if/when I can find them. I'm pretty sure this may become a duplicatehas been explained in the context of the astronauts aboard the ISS; they're both "falling" or oribing the Earth, and up there gravity is about 85.5% that of the surface.