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Catching NameError will not work for the OP, because it will always be raised. See this contrived example.

Steven Rumbalski
– Steven Rumbalski

2012-08-23 14:51:25 +00:00
Commented Aug 23, 2012 at 14:51
@StevenRumbalski Thanks, I don't yet understand why but I'll try to... Anyway, the other way works

Tobias Kienzler
– Tobias Kienzler

2012-08-23 15:12:27 +00:00
Commented Aug 23, 2012 at 15:12
here is the code including the cache the way I understand a cache should work... (if v in cache and cache.append(v) instead of if cache and cache = [v])

Tobias Kienzler
– Tobias Kienzler

2012-08-23 15:33:21 +00:00
Commented Aug 23, 2012 at 15:33

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Correct minor typos or mistakes
Clarify meaning without changing it
Add related resources or links
Always respect the author’s intent
Don’t use edits to reply to the author

create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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