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when toggle format what by license comment
Jan 21, 2016 at 13:03 comment added T4NK3R I do. Used for full-text search (and snippet-display): No random tabs, non-breakers or thingymajigs, please.
Dec 30, 2009 at 18:11 comment added watain EvanCarroll you fail because \s\s+ is definitely different to \s+. \s\s+ would match '\t\t' or '\t\t\t' but NOT '\t'. And that's what it's all about, you don't want replace every f-en single whitespace character.
Dec 30, 2009 at 17:55 comment added Evan Carroll The first one is totally pointless, \s\s+ means, an \s followed by one or more \s+, which can be reduced to a single \s+, the second example is more accurate because we only want to replace double spaces, not newlines, the third is more optimized because it only applies to examples with 2+ spaces. But str.replace(/ +(?= )/g,'');, only applies to examples with 2+ spaces but saves overwriting a space with a space step.
Dec 30, 2009 at 17:45 history edited meder omuraliev CC BY-SA 2.5
added 298 characters in body
Dec 30, 2009 at 17:38 history edited meder omuraliev CC BY-SA 2.5
added 307 characters in body; added 145 characters in body
Dec 30, 2009 at 17:32 history answered meder omuraliev CC BY-SA 2.5