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Python3 print(), markdown formatting
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Tonechas
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You can use the df.ilocdf.iloc function as follows:

for i in range(0, len(df)):
    print(df.iloc[i]['c1'], df.iloc[i]['c2'])

You can use the df.iloc function as follows:

for i in range(0, len(df)):
    print(df.iloc[i]['c1'], df.iloc[i]['c2'])

You can use the df.iloc function as follows:

for i in range(0, len(df)):
    print(df.iloc[i]['c1'], df.iloc[i]['c2'])

You can use the df.ilocdf.iloc function as follows:

for i in range(0, len(df)):
    print df.iloc[i]['c1'], df.iloc[i]['c2']
for i in range(0, len(df)):
    print(df.iloc[i]['c1'], df.iloc[i]['c2'])

You can use the df.iloc function as follows:

for i in range(0, len(df)):
    print df.iloc[i]['c1'], df.iloc[i]['c2']

You can use the df.iloc function as follows:

for i in range(0, len(df)):
    print(df.iloc[i]['c1'], df.iloc[i]['c2'])
added 4 characters in body
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PJay
  • 2.8k
  • 1
  • 16
  • 12

You can use the df.iloc function as follows:

for i in range(0, len(df)):
    print df.iloc[i]['c1'], df.iloc[i]['c2']

You can use the df.iloc function as follows:

for i in range(0, len(df)):
print df.iloc[i]['c1'], df.iloc[i]['c2']

You can use the df.iloc function as follows:

for i in range(0, len(df)):
    print df.iloc[i]['c1'], df.iloc[i]['c2']
Source Link
PJay
  • 2.8k
  • 1
  • 16
  • 12
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