Timeline for answer to How to generate a random 4 digit number not starting with 0 and having unique digits? by Jean-François Fabre
Current License: CC BY-SA 3.0
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9 events
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| Apr 25, 2017 at 18:16 | history | edited | Jean-François Fabre♦ | CC BY-SA 3.0 |
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| Apr 24, 2017 at 19:10 | history | edited | Jean-François Fabre♦ | CC BY-SA 3.0 |
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| Apr 24, 2017 at 18:21 | history | edited | Jean-François Fabre♦ | CC BY-SA 3.0 |
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| Apr 24, 2017 at 17:05 | comment | added | Jean-François Fabre♦ |
but you cannot have 0023. There's only one 0
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| Apr 24, 2017 at 16:41 | comment | added | janscas | if you get 0023, then you have the same problem | |
| Apr 24, 2017 at 16:40 | comment | added | Jean-François Fabre♦ | @TimPeters you're right. Added an alternate solution. | |
| Apr 24, 2017 at 16:39 | history | edited | Jean-François Fabre♦ | CC BY-SA 3.0 |
added 297 characters in body
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| Apr 24, 2017 at 16:36 | comment | added | Tim Peters | Except the allowable outcomes aren't equally likely then; e.g., there are two ways to get 1230, but only one way to get 1234. | |
| Apr 24, 2017 at 16:29 | history | answered | Jean-François Fabre♦ | CC BY-SA 3.0 |