Timeline for answer to How to use Array.from with a XPathResult? by Explosion Pills
Current License: CC BY-SA 4.0
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| Feb 7, 2025 at 0:32 | history | edited | Avindra Goolcharan | CC BY-SA 4.0 |
deduplicate iterateNext() call
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| Jun 27, 2020 at 19:02 | comment | added | Chinoto Vokro |
To avoid duplication and (imo) make it clearer, you could instead do const nodes = []; let node; while (node = xPathResult.iterateNext()) {nodes.push(node);}. Too bad you can't just say while (const node = xPathResult.iterateNext()) {...} since the value isn't used outside the loop.
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| Dec 13, 2017 at 16:25 | vote | accept | ceving | ||
| Oct 30, 2017 at 14:27 | history | answered | Explosion Pills | CC BY-SA 3.0 |