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Active reading [<https://en.wiktionary.org/wiki/built-in#Adjective>]. Interpreted "i.e." as meaning "e.g."
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Peter Mortensen
Peter Mortensen
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It's possible to access for some builtin iterators via __reduce__, e.g.:

xs = iter([8, 23, 45])

for x in xs:
    print("item #{} = {}".format(xs.__reduce__()[-1], x))

But I'd prefer to use enumerate generally

For other builtinbuilt-in iterators (excluding i.e., for example, Generators and others), that cannot have their index retrieved via reduce, see my answer here if interested: Is it possible to get index of the next item from iterator?Is it possible to get index of the next item from iterator?

It's possible to access for some builtin iterators via __reduce__ e.g.:

xs = iter([8, 23, 45])

for x in xs:
    print("item #{} = {}".format(xs.__reduce__()[-1], x))

But I'd prefer to use enumerate generally

For other builtin iterators (excluding i.e. Generators and others) that cannot have their index retrieved via reduce see my answer here if interested: Is it possible to get index of the next item from iterator?

It's possible to access for some builtin iterators via __reduce__, e.g.:

xs = iter([8, 23, 45])

for x in xs:
    print("item #{} = {}".format(xs.__reduce__()[-1], x))

But I'd prefer to use enumerate generally

For other built-in iterators (excluding, for example, Generators and others), that cannot have their index retrieved via reduce, see my answer here if interested: Is it possible to get index of the next item from iterator?

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Ben Tonks
Ben Tonks
  • 79
  • 1
  • 8

It's possible to access for some builtin iterators via __reduce__ e.g.:

xs = iter([8, 23, 45])

for x in xs:
    print("item #{} = {}".format(xs.__reduce__()[-1], x))

But I'd prefer to use enumerate generally

For other builtin iterators (excluding i.e. Generators and others) that cannot have their index retrieved via reduce see my answer here if interested: Is it possible to get index of the next item from iterator?