jQuery dialog validation using jquery.validate()

Question

When I click on the submit button, it still submits the form without validating the fields. I looked on other solutions here too, but no question mentions about what to do in the click function on submit.

Here's my code: https://jsfiddle.net/ishtiaq156/an1xqoxz/

Form:

      $('#submitContact').click(function() {
        var customerId = $('#customerId').val();
        var formData = $('#addCustomerForm').serialize();

        $.ajax({
          url: "/abc/admin/customer/" + customerId + "/addContact",
          type: "POST",
          dataType: "json",

          data: formData,
          success: function(data) {
            location.reload();
          },
          failure: function(errMsg) {
            alert(errMsg);
          }

        });
      });

JavaScript:

 $('#submitContact').click(function() {
                var customerId = $('#customerId').val();
                var formData = $('#addCustomerForm').serialize();

                $.ajax({
                  url: "/abc/admin/customer/" + customerId + "/addContact",
                  type: "POST",
                  dataType: "json",

                  data: formData,
                  success: function(data) {
                    location.reload();
                  },
                  failure: function(errMsg) {
                    alert(errMsg);
                  }

                });
              });

Answer 1

One way I've done it in the past is adding a submit handler to the validation code which calls your ajax function. Then you can change your button to type="submit"

$('#addCustomerForm').validate({
    rules: {
        /* removed for brevity */
    },
    messages: {
        /* removed for brevity */
    },
    submitHandler: function (form) {
        updateRecord();
        /* $("#dialog-form").dialog("close"); -  if using dialog */
    }
    /* ....add other options as needed */
});

function updateRecord() {
    var customerId = $('#customerId').val();
    var formData = $('#addCustomerForm').serialize();

    $.ajax({
        url: "/abc/admin/customer/" + customerId + "/addContact",
        type: "POST",
        dataType: "json",

        data: formData,
        success: function(data) {
           location.reload();
        },
        failure: function(errMsg) {
           alert(errMsg);
        }
    });
} 

Also, you can send all your form variables using data rather than adding some to the URL:

data: {
    customerId: customerId,
    addContact: "addContact",
    ...add other form fields 
}

Answer 2

you should post here console log

make sure you have included jquery validation plugin

or download it