Basically I have the inverse of this problem: Python Time Seconds to h:m:s
I have a string in the format H:MM:SS (always 2 digits for minutes and seconds), and I need the integer number of seconds that it represents. How can I do this in python?
For example:
etc
def get_sec(time_str):
"""Get seconds from time."""
h, m, s = time_str.split(':')
return int(h) * 3600 + int(m) * 60 + int(s)
print(get_sec('1:23:45'))
print(get_sec('0:04:15'))
print(get_sec('0:00:25'))
float(s) instead.ts = '1:23:45'
secs = sum(int(x) * 60 ** i for i, x in enumerate(reversed(ts.split(':'))))
print(secs)
s and m:s strings like "53" and "2:41" correctly
int(x) to float(x) and it'll handle decimal seconds, plus it doesn't need a leading zero for hour. VTT timestamps omit the leading 0 hour until hour > 1.Using datetime module
import datetime
t = '10:15:30'
h,m,s = t.split(':')
print(int(datetime.timedelta(hours=int(h),minutes=int(m),seconds=int(s)).total_seconds()))
Output: 36930
re for this. Strings have a split method: str.split(). Much cleaner to just use t.split(':') instead of re.split(':', t).
h, m, s = [int(x) for x in t.split(':')].Without many checks, and assuming it's either "SS" or "MM:SS" or "HH:MM:SS" (although not necessarily two digits per part):
def to_seconds(timestr):
seconds= 0
for part in timestr.split(':'):
seconds= seconds*60 + int(part, 10)
return seconds
>>> to_seconds('09')
9
>>> to_seconds('2:09')
129
>>> to_seconds('1:02:09')
3729
This is a different “spelling” of FMc's answer :)
minutes or hours part in a neat, single function, and without using any extra library. Kudos!Using datetime module is also posible and more robust
import datetime as dt
def get_total_seconds(stringHMS):
timedeltaObj = dt.datetime.strptime(stringHMS, "%H:%M:%S") - dt.datetime(1900,1,1)
return timedeltaObj.total_seconds()
datetime.strptime parses the string according to format %H:%M:%S, and it creates a datetime object as year 1900, month1, day 1, hour H, minute M, and second S.
That's why to get the total of seconds is necessary to subtract the year, month and day.
print(get_total_seconds('1:23:45'))
>>> 5025.0
print(get_total_seconds('0:04:15'))
>>> 255.0
print(get_total_seconds('0:00:25'))
>>>25.0
For %H:%M:%S.%f
def get_sec(time_str):
h, m, s = time_str.split(':')
return int(h) * 3600 + int(m) * 60 + float(s)
You can use lambda and reduce a list and the fact that m=60s and h=60m. (see "Reducing a List" at http://www.python-course.eu/lambda.php)
timestamp = "1:23:45"
seconds = reduce(lambda x, y: x*60+y, [int(i) for i in (timestamp.replace(':',',')).split(',')])
You can split the time into a list and add each individual time component, multiplying the hours component by 3600 (the number of seconds in an hour) and the minutes component by 60 (number of seconds in a minute), like:
timeInterval ='00:35:01'
list = timeInterval.split(':')
hours = list[0]
minutes = list[1]
seconds = list[2]
total = (int(hours) * 3600 + int(minutes) * 60 + int(seconds))
print("total = ", total)
I didn't really like any of the given answers, so I used the following:
def timestamp_to_seconds(t):
return sum(float(n) * m for n,
m in zip(reversed(time.split(':')), (1, 60, 3600))
)
Expanding on @FMc's solution which embodies half of Horner's method. Advantage of Horner's method: Skip reversing the list, avoid power calculation.
from functools import reduce
timestamp = "1:23:45"
seconds = reduce(lambda s, d: s * 60 + int(d), timestamp.split(":"), 0)
or, if you dislike reduce (as does Guido van Rossum and @0xc0de below):
timestamp = "1:23:45"
seconds = 0
for d in timestamp.split(":"):
seconds = seconds * 60 + int(d)
If you prefer zip (as does @nathan-rice below):
from itertools import accumulate, repeat
from operator import mul
def timestamp_to_seconds(t):
return sum(int(n) * m for n, m in
zip(reversed(t.split(":")), accumulate(repeat(60), func=mul, initial=1)))
reduced readability. +1 for those cases, I am not a fan of reduce() though and would prefer to avoid these.I liked tzot's answer above the best for my purposes because my H:M:S are human created and the can have float seconds part Here is my small modification
def hms_to_seconds(timestr:str)->float:
"""Get seconds from time.
:param timestr: hh:mm:ss.xxx string or mm:s.xxx or simply s.xxx where xxx is the fraction of seconds
:returns: time in float seconds
"""
seconds= 0.
for part in timestr.split(':'):
seconds= seconds*60. + float(part)
return seconds
>>> hms_to_seconds('3.00')
3.0
>>> hms_to_seconds('1:3.00')
63.0
>>> hms_to_seconds('1:0:3.5')
3603.5
Another alternative if you have days on string:
def duration2sec(string):
if "days" in string:
days = string.split()[0]
hours = string.split()[2].split(':')
return int(days) * 86400 + int(hours[0]) * 3600 + int(hours[1]) * 60 + int(hours[2])
else:
hours = string.split(':')
return int(hours[0]) * 3600 + int(hours[1]) * 60 + int(hours[2])
Just a simple generalization to the great response of taskinoor
In the context of my problem the format is similar, but includes AM or PM.
Format 'HH:MM:SS AM' or 'HH:MM:SS PM'
For this case the function changes to:
def get_sec(time_str):
"""Get Seconds from time."""
if 'AM' in time_str:
time_str = time_str.strip('AM')
h, m, s = time_str.split(':')
seconds = int(h) * 3600 + int(m) * 60 + int(s)
if 'PM' in time_str:
time_str = time_str.strip('PM')
h, m, s = time_str.split(':')
seconds = (12 + int(h)) * 3600 + int(m) * 60 + int(s)
return seconds
In Pandas using @JayRizzo 's cool function and a list comprehension:
def get_sec(time_str):
"""Get Seconds from time."""
h, m, s = time_str.split(':')
return int(h) * 3600 + int(m) * 60 + int(s)
df['secs']=[get_sec(x) for x in df['original_time_string']]
