Timeline for answer to How do I use a Bash variable (string) containing quotes in a command? by Gordon Davisson
Current License: CC BY-SA 3.0
Post Revisions
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 16, 2020 at 5:17 | comment | added | Gordon Davisson |
@mvorisek If I understand what you mean (using a non-array variable, and no eval or equivalent), then it's impossible.
|
|
| Nov 15, 2020 at 23:18 | comment | added | mvorisek |
Thanks! Anything without intermediate variable (and not modifiying the command itself like with eval prefix) is impossible, right?
|
|
| Nov 24, 2011 at 22:39 | vote | accept | multipolygon | ||
| Nov 24, 2011 at 16:25 | history | edited | Gordon Davisson | CC BY-SA 3.0 |
Typo fix
|
| Nov 24, 2011 at 6:38 | history | answered | Gordon Davisson | CC BY-SA 3.0 |