Revisions to Displaying file names with contents when using the "cat" command

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You could easily write a tiny script doing just that,

for f; 
do 
  echo "This is from $f";
  cat -- "$f";
done

for f; 
do 
  echo "This is from $f";
  cat -- "$f";
done

You could easily write a tiny script doing just that,

for f; 
do 
  echo "This is from $f";
  cat -- "$f";
done

You could easily write a tiny script doing just that,

for f; 
do 
  echo "This is from $f";
  cat -- "$f";
done

No need for `in "$@"`.

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edited Apr 29, 2024 at 9:49

Stephen Kitt

You could easily write a tiny script doing just that,

for f in "$@";f; 
do 
  echo "This is from $f";
  cat -- "$f";
done

You could easily write a tiny script doing just that,

for f in "$@"; 
do 
  echo "This is from $f";
  cat -- "$f";
done

You could easily write a tiny script doing just that,

for f; 
do 
  echo "This is from $f";
  cat -- "$f";
done

typo fixed, use ; before do

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EsmaeelE

You could easily write a tiny script doing just that,

for f in "$@""$@"; do;
do 
  echo "This is from $f";
  cat -- "$f";  
done

You could easily write a tiny script doing just that,

for f in "$@" do; echo "This is from $f"; cat -- "$f"; done

You could easily write a tiny script doing just that,

for f in "$@"; 
do 
  echo "This is from $f";
  cat -- "$f"; 
done

fixed missing double quotes, and $* to $@

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edited Aug 28, 2012 at 23:44

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Post Migrated Here from stackoverflow.com (revisions)

occurred Aug 28, 2012 at 16:23

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answered Aug 28, 2012 at 15:46

juampa

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