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lang-bash
*acts as a regex expression? I thought that it was a special array... although surprise me that there is no such array...*[0] or *[1]gives me some file name... now I'm puzzled.*[0]in zsh would expand to filenames that start with anything (or nothing) followed by any of the following characters:0. The square brackets designates a set of characters in that position. You likely have files that end with a zero in your current directory. To tell zsh to give you back the first element of a*wildcard, you'd use parenthesis for array syntax:print -l *([1])-- noting that zsh arrays start at 1 unless you set$KSH_ARRAYS