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Thanks @nezabudka, that's correct. However, I've just realized that my desired output was wrong. I've updated it. Any idea how to remove the 1st line using -v ?

Wolf
– Wolf

2020-10-09 06:07:26 +00:00
Commented Oct 9, 2020 at 6:07
1

If I'm not wrong, \S will need to match a character, which means that the second expression won't return lines where the spaces are located at the extreme start or end of the line.

Kusalananda
– Kusalananda ♦

2020-10-09 06:51:31 +00:00
Commented Oct 9, 2020 at 6:51
1

@Kuslananda, Thanks. Of course, only for the specific case from the given example. Otherwise it should look like this: grep -E '(^|\S)\s{1,3}(\S|$)'

nezabudka
– nezabudka

2020-10-09 17:09:51 +00:00
Commented Oct 9, 2020 at 17:09

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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
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[example](https://example.com)

<a href="https://example.com">example</a>

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