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I'm working on a project for a robot and I'm trying to make a menu that can run on start up where the user can calibrate the mid-point for the servos (so they're stationary) and the ldrs so it can tell between black lines and white paper. So, I've made the menu a switch case where it calls the calibration when user enters a value, the calibration routines are their own functions.

What I want to know how to do is how to make it so when the user is finished with a calibrator it will go back to the menu function and also how to get the menu to exit on user input. So far when the menu calls a function it will just loop on it.

The menu:

void Menu(){

  Serial.println("|****************************|");
  Serial.println("|**|Ardnoid Configuration |**|");
  Serial.println("|**|        Menu          |**|");
  Serial.println("|****************************|");
  Serial.println("");
  Serial.println("Select one of the following options:");
  Serial.println("1 LDR configuration");
  Serial.println("2 Servo calibration");
  Serial.println("3 Exit configuration menu");

  while(!Serial.available()){}
  int i = Serial.parseInt();

  switch(i){

  case 1:
    break;
  case 2:
    while(srvConOn == true){
      srvConfig();
      }
    break;strong text
  case 3:
    Serial.println("Leaving configuration menu"); 
    break;
  default:
    Serial.println("Unrecognized command, try again!");
    } 
 }

and the servo calibration: 

void srvConfig(){

Serial.println("");
Serial.println("Begin servo stop calibration routine");

int x = 0;

  while(x == 0){

    Serial.println("Enter values for servos until both are stationary");
    delay(100);

    Serial.println("Enter value for left servo");
    while (!Serial.available()) {;}
    left = Serial.parseInt();
    Serial.println(left);
    delay(100);

    Serial.println("Enter value for right servo");
    while (!Serial.available()) {;}
    right = Serial.parseInt();
    Serial.println(right);
    delay(100);

    srvR.write(right);
    srvL.write(left);

    Serial.println("have both servos stopped?");
    Serial.println("1 = Yes | 2 = No"); 

    int j;
    while (!Serial.available()) {;}
    j = Serial.parseInt();

    if (j == 1) {
      Serial.println("Saving calibration");
      EEPROM.write(leftMid, left);
      EEPROM.write(rightMid, right);
      srvConOn == false; 
      x == 1;
      } else if (j == 2) {
        Serial.println("Try again");
        Serial.println();
        }
  }
}
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1 Answer 1

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You could put your switch/case inside an infinite loop, and return from the Menu() function when the user presses '3'. E.g.:

void Menu() {
    Serial.println(menu_banner);
    for (;;) {
        switch (Serial.read()) {
            case '1': ldrConfig(); break;
            case '2': srvConfig(); break;
            case '3': return;
            default: continue;  // includes the case 'no input'
        }
    }
}
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4
  • Good work around for the menu! But how would you suggest getting from the functions back to the menu switch? Commented Dec 5, 2017 at 21:05
  • @ROff: This is already handled here: when srvConfig() returns, we break out of the switch, then we get into another iteration of the infinite for (;;) loop, then back to switch (Serial.read()). The infinite loop is only broken when the user types '3'. Commented Dec 5, 2017 at 21:10
  • I just ran it through and it seems like whenever I try to save the srvConfig instead of returning to the menu it will just run srvConfig again Commented Dec 5, 2017 at 21:18
  • @ROff: In srvConfig(), replace x == 1 with x = 1, or more simply with return (and then get rid of x).. Commented Dec 5, 2017 at 21:57

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