Scanning multiple strings in one line to a pointers array in C [closed]

The problem is line *(words+j) = &str;. It says that we want words[j] or *(words+j) to point to where the str is pointing. So, at the end of the while, all the words are pointing to the same str with the content of red. It can be solved using strcpy method from string.h header, which copies the values not simply change the reference.

strcpy(*(words + j), str);

or

strcpy(words[j]), str);

If you don't want to use string header, you can copy the characters in str into the words[j] manully.

Also, you have to handle the last string before the new line character. One way is putting the str definition out of the while, and repeat the copy procedure after the while statement once more like this:

    } // end of the while
str[i] = '\0';
strcpy(words[j], str);

My preferred way to solve this question is:

int readLine(char *line)
{
    int spaces = 0;
    char *p = line;
    char c;
    while ((c = getchar()) != '\n') {
        if (c == ' ')
            spaces++;
        *p++ = c;
    }
    *p = '\0';
    return spaces + 1;
}

void strSave(char **buf, char *line)
{
    char *p = line, *q = line;
    int i = 0;
    while (*p != '\0') {
        if (*p == ' ') {
            buf[i] = malloc((p - q + 1) * sizeof(char));
            strncpy(buf[i], q, p-q);
            p++;
            i++;
            q = p;
        } else {
            p++;
        }
    }
    buf[i] = malloc((p - q + 1) * sizeof(char));
    strncpy(buf[i], q, p-q);

}

int main()
{
    char **buf;
    char line[1024];
    int stringCounts;
    char c;

    stringCounts = readLine(line);
    buf = malloc((stringCounts) * sizeof(char *));

    strSave(buf, line);

    for (int k = 0; k < stringCounts; k++) {
        printf("%s\n", buf[k]);
        free(buf[k]);
    }

    free(buf);

    return 0;
}

Happy to explain it more if someone's interested. I know this question was off-topic, but couldn't resist.