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std::unordered_set<Key,Hash,KeyEqual,Allocator>::end, std::unordered_set<Key,Hash,KeyEqual,Allocator>::cend

From cppreference.com
 
 
 
 
iterator end() noexcept;
(1) (since C++11)
(constexpr since C++26)
const_iterator end() const noexcept;
(2) (since C++11)
(constexpr since C++26)
const_iterator cend() const noexcept;
(3) (since C++11)
(constexpr since C++26)

Returns an iterator past the last element of *this.

This returned iterator only acts as a sentinel. It is not guaranteed to be dereferenceable.

range-begin-end.svg

Contents

[edit] Return value

Iterator past the last element.

[edit] Complexity

Constant.

Notes

Because both iterator and const_iterator are constant iterators (and may in fact be the same type), it is not possible to mutate the elements of the container through an iterator returned by any of these member functions.

[edit] Example

#include <iostream>
#include <unordered_set>
 
struct Point { double x, y; };
 
int main()
{
    Point pts[3] = {{1, 0}, {2, 0}, {3, 0}};
 
    // points is a set containing the addresses of points
    std::unordered_set<Point*> points = { pts, pts + 1, pts + 2 };
 
    // Change each y-coordinate of (i, 0) from 0 into i^2 and print the point
    for (auto iter = points.begin(); iter != points.end(); ++iter)
    {
        (*iter)->y = ((*iter)->x) * ((*iter)->x); // iter is a pointer-to-Point*
        std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") ";
    }
    std::cout << '\n';
 
    // Now using the range-based for loop, we increase each y-coordinate by 10
    for (Point* i : points)
    {
        i->y += 10;
        std::cout << "(" << i->x << ", " << i->y << ") ";
    }
}

Possible output:

(3, 9) (1, 1) (2, 4) 
(3, 19) (1, 11) (2, 14)

[edit] See also

returns an iterator to the beginning
(public member function) [edit]
(C++11)(C++14)
returns an iterator to the end of a container or array
(function template) [edit]