Create Count of Smaller Numbers After Self

LeetcodeProblems/Algorithms/Count of Smaller Numbers After Self

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+Question:
+Input: nums = [5,2,6,1]
+Output: [2,1,1,0]
+Explanation:
+To the right of 5 there are 2 smaller elements (2 and 1).
+To the right of 2 there is only 1 smaller element (1).
+To the right of 6 there is 1 smaller element (1).
+To the right of 1 there is 0 smaller element.
+
+Example 2:
+
+Input: nums = [-1]
+Output: [0]
+Example 3:
+
+Input: nums = [-1,-1]
+Output: [0,0]
+
+
+
+function countSmaller(nums) {
+    const result = [];
+    for (let i = 0; i < nums.length; i++) {
+        let count = 0;
+        for (let j = i + 1; j < nums.length; j++) {
+            if (nums[j] < nums[i]) {
+                count += 1;
+            }
+        }
+        result.push(count);
+    }
+    return result;
+}