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std::has_virtual_destructor

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has_virtual_destructor
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Definido no cabeçalho <type_traits>
template< class T >
struct has_virtual_destructor;
 (desde C++11)
Se T é um tipo com um destrutor virtual, fornece o membro constante value true igual. Para qualquer outro tipo, é value false.
Original:
If T is a type with a virtual destructor, provides the member constant value equal true. For any other type, value is false.
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Índice

Herdado de std::integral_constant

Member constants

value
[estática]
true se T has a virtual destructor , false contrário
Original:
true if T has a virtual destructor , false otherwise
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(membro estático público constante)

Member functions

operator bool
converte o objeto em bool, retorna value
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converts the object to bool, returns value
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(função pública membro)

Member types

Tipo
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Type
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 Definition
value_type bool
type std::integral_constant<bool, value>

[editar] Notas

Se uma classe tem um destrutor pública virtual, que pode ser derivado e, o objeto derivado pode ser excluído com segurança através de um ponteiro para o objeto base (C++FAQ Lite 20.7)
Original:
If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (C++FAQ Lite 20.7)
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[editar] Exemplo

#include <iostream>
#include <type_traits>
#include <string>
#include <stdexcept>
 
int main()
{
    std::cout << std::boolalpha
              << "std::string has a virtual destructor? "
              << std::has_virtual_destructor<std::string>::value << '\n'
              << "std::runtime_error has a virtual destructor? "
              << std::has_virtual_destructor<std::runtime_error>::value << '\n';
}

Saída: 

std::string has a virtual destructor? false
std::runtime_error has a virtual destructor? true

[editar] Veja também

(C++11)
(C++11)
(C++11)
verifica se um tipo tem um destrutor não-excluído
Original:
checks if a type has a non-deleted destructor
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(modelo de classe) [edit]
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