PHP - Referencing an array value in a foreach loop

Question

This array is being populated with URL's using a for each loop (they are page number URL's)

$pageNumberLinks[] = "<a href= URL_code>".$page_number . "</a>";

I am trying to reference the $page_number variable value in each URL in the array as the foreach loop executes, so I can use an if statement to execute code based on the $page_number value. $PageNumberLinks->page_number is not working. Any advice?

foreach ($pageNumberLinks as $PageNumberLinks) {
    if ($PageNumberLinks->page_number == $z ) {
        // execute code
    } else {
        // execute code
    }
}

What if you define $pageNumberLinks[$page_number] = "<a href= URL_code>".$page_number . "</a>"; ? This way, you will be able to loop through the indexes properly. — fedorqui
– fedorqui, Commented Mar 15, 2014 at 22:06
The $page_number variable isn't accessible in the way your are using it. The -> is attempting to access an object property. Unless $PageNumberLinks is an object, then it won't work. — Crackertastic
– Crackertastic, Commented Mar 15, 2014 at 22:06
Good advice! The code works! But the foreach loop isn't displaying the URL's. It is only displaying numbers. — Dean Olsen
– Dean Olsen, Commented Mar 16, 2014 at 2:29

AbraCadaver · Accepted Answer · 2014-03-15 22:11:39Z

1

Just do:

$pageNumberLinks[$page_number] = "<a href= URL_code>".$page_number . "</a>";

foreach ($pageNumberLinks as $key => $val) {
    if ($key == $z) {
        // execute code
    } else {
        // execute code
    }
}

answered Mar 15, 2014 at 22:11

AbraCadaver

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4 Comments

PeeHaa Over a year ago

So basically what @fedorqui said 6 minutes ago in the comments?

AbraCadaver Over a year ago

@PeeHaa: Yes, basically, except this is an answer not a comment.

Dean Olsen Over a year ago

Good advice! The code works! But the foreach loop isn't displaying the URL's. It is only displaying numbers.

AbraCadaver Over a year ago

@DeanOlsen: My foreach doesn't display anything. That should be a trivial exercise depending on what you want to display.

Ernest Nowacki · Accepted Answer · 2014-03-15 22:11:25Z

0

You should build your array with proper indexes which will make it easier for you to loop thru:

$pageNumberLinks[$page_number] = "<a href= URL_code>".$page_number . "</a>";

Then you create a loop like

foreach($pageNumberLinks as $pageNumber => $link){    
  if(  $pageNumber === $z ){
    //do code here
  }else{
   //do some code here
  }    
}

answered Mar 15, 2014 at 22:11

Ernest Nowacki

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