Python: regex to parse URL components

Question

Lets say this is my URL string:

https://stackexchange.com/oauth/login_success/#access_token=xxxxxx))&expires=86400

I want to parse just the access token part "xxxxxx))"

This is what I've done so far:

from urllib.parse import urlparse
strr = "https://stackexchange.com/oauth/login_success/#access_token=xxxxxx))&expires=86400"

o = urlparse(strr)

print(o.fragment)

The output I'm getting is:

access_token=xxxxxx))&expires=86400

What's the best way from here to get only the "xxxxxx))" part? Use regex?

pydoc3 urllib.parse.parse_qs

larsks
– larsks

2016-04-04 21:06:18 +00:00
Commented Apr 4, 2016 at 21:06 — larsks
– larsks, Commented Apr 4, 2016 at 21:06

alecxe · Accepted Answer · 2016-04-04 21:11:09Z

3

Here is one way to do that - first use urlparse() and then call parse_qs() on the fragment:

>>> from urllib.parse import parse_qs, urlparse
>>> 
>>> strr = "https://stackexchange.com/oauth/login_success/#access_token=xxxxxx))&expires=86400"
>>> o = parse_qs(urlparse(strr).fragment)
>>> print(o['access_token'])
['xxxxxx))']

answered Apr 4, 2016 at 21:11

alecxe

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Poul Bak · Accepted Answer · 2016-04-04 21:12:02Z

0

You can use a regular expression:

(?<=access_token=)[^\)]*

answered Apr 4, 2016 at 21:12

Poul Bak

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