Curl command to Python request - doesn't work

Question

I'm trying to convert the following curl (which works fine) to Python code:

curl -X POST https://api.example.com/c \
-H 'Authorization: Bearer {token}' \
-H 'content-type: multipart/form-data' \
-F 'attachment[c_id]=1111' \
-F 'attachment[file][email protected]'

I've tried two different options:

Option #1:

import requests

headers = {
    'Authorization': 'Bearer {token}',
    'content-type': 'multipart/form-data',
}

files = {
    'attachment[c_id]': (None, '1111'),
    'attachment[file]': ('file.png', open('file.png', 'rb')),
}

response = requests.post('https://api.example.com/c',
                         headers=headers, files=files)

Option #2:

import requests
from requests_toolbelt.multipart.encoder import MultipartEncoder

headers = {
    'Authorization': 'Bearer {token}',
    'content-type': 'multipart/form-data',
}

multipart_data = MultipartEncoder(
    fields=(
        ('attachment[file]', open('file.png', 'rb')),
        ('attachment[c_id]', '1111')
    ))

response = requests.post('https://api.example.com/c',
                         headers=headers, data=multipart_data)

Both options failed with the following error:

requests.exceptions.ConnectionError: ('Connection aborted.', BrokenPipeError(32, 'Broken pipe'))

So, it means that Python code works in a different way because curl works just fine.

I've tried https://curl.trillworks.com/ - it didn't help, unfortunately. How can I do the same on Python?

Have you looked at getpostman.com? you can import a curl command , run it, and export it as code in many languages. — Daniel Dror, Commented Jul 10, 2019 at 9:53
@DanielDubovski , I've tried, postman generates "trash" code with payload saved as a string. Not really useful, unfortunately. — Timur Nurlygayanov, Commented Jul 10, 2019 at 10:09

Timur Nurlygayanov · Accepted Answer · 2019-07-10 10:23:15Z

1

I've just found the solution - the problem was in the Content-Type headers.

Important: when we use the "files" parameter for request, we shouldn't use the Content-Type header, requests will set it on his own (the size of payload should be in this header, and requests library will add this information automatically).

The following code works just fine:

import requests

headers = {
    'Authorization': 'Bearer {token}',
}

files = (
    ('attachment[c_id]', (None, '1111')),
    ('attachment[file]', ('file.png', open('file.png', 'rb')))
)

response = requests.post('https://api.example.com/c',
                         headers=headers, files=files)

answered Jul 10, 2019 at 10:23

Timur Nurlygayanov

1,2653 gold badges13 silver badges24 bronze badges

Does it work if you make files a dictionary again but with the content type header removed?
– Dan
Commented Jul 10, 2019 at 10:30
1

@Dan, yes, it works with both dict and tuple for files, only Content-Type header should be removed
– Timur Nurlygayanov
Commented Jul 10, 2019 at 10:55

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