Python Permutations - Obtaining full set of outcomes with conditions

Question

I have the following list of variables that take on a Boolean value:

outcome_value=['A','B','C']

outcome_type=[True,False]

I want to obtain the full list for possible outcomes for the three variables. The conditions I want are when A=True then B,C = False; when B=True the others equal False and so on. in other words:

outcomes_all = [(True, False, False), (False, True, False), (False, False, True)]

What code could I use to obtain the above? Please note this is a simplification of what I am looking to do I am looking to get code I could use to extend to a more complex list of outcomes.

Only thing i can think of so far is as follows

import random
        for o in outcome_value:
            p=random.choice(outcome_type)
            print(p)

which of course only produces one set of True False values and can produce more than one True value which I don't want. I have been trying to build out if statements as well but keep running down blind alleys with it.

Does anyone have any ideas on how to do this? Haven't seen any threads with a similar question yet.

Thanks

Edit: thinkI may have oversimplified my questions so will post a more complex example

outcome_value=['A','B','C','D','E','F']

outcome_type=[True,False]

I'm looking for all possible permutations of True and False but want to specify conditions such as:

outcome_type of A must not equal outcome_type of B, same for C and D, E and F
if A=True, then C,E must equal False (in addition to condition 1 for B being met also)
if C=True, A,E=False (in addition to condition 1 for D being met also)
if E=True, A,C=False (in addition to condition 1 for F being met also)

Therefore final outcome would be like follows:

[(True, False, False, True ,False ,True), (False, True, False, False, False ,True), (False, False, True, True, True, False)]

Hope that makes sense.

Alain T. · Accepted Answer · 2020-12-19 21:45:09Z

2

I'm not sure you're covering all cases in your question but if you're only looking for one True value in the trio for each position, you can do this:

outcome_value = ['A','B','C']
outcome_type  = [True,False]

outcomes_all = [ tuple(outcome_type[t!=p] for t in outcome_value) for p in outcome_value ]

# [(True, False, False), (False, True, False), (False, False, True)]

This is simple enough but I suspect there's more to it than that. Given that you requested the full list, random should not come into play.

edited Dec 19, 2020 at 21:45

answered Dec 19, 2020 at 21:37

Alain T.

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4 Comments

Daniel Hao Over a year ago

This seems to be a sensible approach. However, I got different results here:?[(False, True, True), (True, False, True), (True, True, False)]

Alain T. Over a year ago

Fixed, I didn't realize the True and False were inverted in outcome_type

python_beginner Over a year ago

thanks, I'm getting two True values when I run the above though? [(False, True, True), (True, False, True), (True, True, False)]...dont think this would work anyway since if I want to extend the list (ie add D, E, F etc) there will be more than one True and False value for each. Therefore am more looking for specific code that recognizes the values so that if say A= True then set B,C to False, but others could still be either true or false

Alain T. Over a year ago

did you copy it after the fix ? (outcome_type[t!=p]) I tried is again and it works as indicated

Arn · Accepted Answer · 2020-12-19 21:40:58Z

2

You can get the list of values by filtering out the Cartesian product:

from itertools import product
outcomes_all = list(filter(
    lambda x: sum(x) == 1,
    product(outcome_type, repeat=3)
))

That would be the output:

>>> outcomes_all
[(True, False, False), (False, True, False), (False, False, True)]

answered Dec 19, 2020 at 21:40

Arn

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Comments

Muteshi · Accepted Answer · 2020-12-19 21:37:52Z

0

You mean like this?

import itertools
outcome_value=['A','B','C']

outcome_value = False,False,True

combin = itertools.permutations(outcome_value,3)

print(list(combin))

This is the output

[(False, False, True), (False, True, False), (False, False, True), (False, True, False), (True, False, False), (True, False, False)]

answered Dec 19, 2020 at 21:37

Muteshi

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