I have following 2 files as below:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<script>
function init(){
document.getElementById("mytest").innerHTML= "Results after rendering...";
}
</script>
<body onload="init();"><div id="mytest">OK</div>
</body>
</html>
The second page usually give the alert popup all source code of first page.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<script>
xmlhttp.open("GET", "test.html",true);
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState==4) {
alert(xmlhttp.responseText)
}
}
xmlhttp.send(null)
</script>
<body>
</body>
</html>
All I want to do is I would like to get ONLY source code after rendering. How can get all code after rendering instead of getting all original code. So i can read < div id="mytest">Results after rendering...< / div> when I try with XMLHTTP. How can I do how to get the code which are already render for page, I want only with classic Javascript or DOM, I don't want with Jquery, JSON, Mootool at all. thanks in advance.