If and else statement using diff -q

Question

So I'm trying to write an if else statement which involves the use of diff -q. So, let's say I have two files hi.txt and hello.txt and I store them into variables called hi and hello respectively. I have this piece of code

if [ diff -q $hi $hello ]; then
  echo "these files are the same"
else 
  echo "these files are not the same"
fi

No matter what hi.txt and hello.txt contain, even if they have exactly the same content. I get an error saying

./(name of script) line (line with [diff -q hi hello]) [: too many arguments.

What part of my syntax is wrong?

SparedWhisle · Accepted Answer · 2015-10-02 01:30:11Z

8

You don't put diff in brackets
The Syntax to use variable is $hi

so the resulting script is:

if diff -q $hi $hello; then
echo "these files are the same"
else
echo "these files are not the same"
fi

answered Oct 2, 2015 at 1:30

SparedWhisle

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5

if the answer works for you, don't just say thanks - accept it. meta.stackexchange.com/questions/23138/…

cas
– cas

2015-10-02 02:08:56 +00:00
Commented Oct 2, 2015 at 2:08

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