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Assuming $x\ge1$. How to go from $$ \frac{\sqrt {x-1}+\sqrt{x+1}}{\sqrt {x-1}-\sqrt{x+1}} $$ to $$ -\sqrt{x^2-1}-x $$ ?

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    $\begingroup$ multiply top & bottom by $\sqrt {x-1}+\sqrt{x+1}$. $\endgroup$ Commented Feb 25, 2018 at 0:29

2 Answers 2

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divide and multiply by $(\sqrt{x-1}+ \sqrt{x+1})$ to get the answer

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  • $\begingroup$ I'd suggest you learn and use mathjax. $\endgroup$ Commented Feb 25, 2018 at 0:43
  • $\begingroup$ Here is a tutorial on how to typeset mathematics on this site. $\endgroup$ Commented Feb 25, 2018 at 0:46
  • $\begingroup$ Thanks, i really needed it $\endgroup$ Commented Feb 25, 2018 at 1:01
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  • $\frac{\sqrt{x-1}+\sqrt{x+1}}{\sqrt{x-1}-\sqrt{x+1}}\hspace{19.7em} $ Original Problem
  • $\frac{\sqrt{x-1}+\sqrt{x+1}}{\sqrt{x-1}-\sqrt{x+1}}\times\frac{\sqrt{x-1}\sqrt{x+1}}{\sqrt{x-1}\sqrt{x+1}}\hspace{14.5em}$ Strategically Multiply by 1.
  • $\frac{\left(\sqrt{x-1}\sqrt{x-1}\right)+\left(\sqrt{x+1}\sqrt{x-1}\right)+\left(\sqrt{x-1}\sqrt{x+1}\right)+\left(\sqrt{x+1}\sqrt{x+1}\right)}{\left(\sqrt{x-1}\sqrt{x-1}\right)-\left(\sqrt{x+1}\sqrt{x-1}\right)+\left(\sqrt{x-1}\sqrt{x+1}\right)-\left(\sqrt{x+1}\sqrt{x+1}\right)}\hspace{5em}$ Distributive Property
  • $\frac{\left(x-1\right)+2\left(\sqrt{x+1}\sqrt{x-1}\right)+\left(x+1\right)}{\left(x-1\right)-\left(x+1\right)}\hspace{14.5em}$ Simplify
  • $-\left(x+\left(\sqrt{x+1}\sqrt{x-1}\right)\right)\hspace{13.5em}$ Simplify
  • $-x-\sqrt{x^{2}-1}\hspace{17.6em}$ Rearrange
  • $\boxed{-\sqrt{x^{2}-1}-x}\checkmark$$\hspace{16em}$ Final Solution
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