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1 vote
1 answer
55 views

Why does Mathematica plot a function with a discontinuity as if one does not exist? [duplicate]

I wrote the code below to plot the function shown over two regions. Mathematica plots the function across the two regions (r from 0 to 2) without recognizing a discontinuity exists at r = 1 (a divide ...
user42700's user avatar
  • 2,017
0 votes
0 answers
58 views

How to plot a graph with intersections, asymptotes and turning points?

Is there a mathematica function that for some function like (x^2-1)/x it labels the intersections, asymptotes and turning points? I'm new to mathematica, thanks ...
CatTitan's user avatar
0 votes
0 answers
45 views

How to arrange an array to make the ListContourPlot

I have an array of chisquare values for two parameters \alpha and a. The array is calculated for function of two parameter \alpha, a ...
Amnish's user avatar
  • 57
3 votes
1 answer
273 views

How can I make all the lines within the polygon turn gray in that region?

How can I make all the lines within the polygon turn gray in that region? ...
hana's user avatar
  • 2,602
2 votes
3 answers
259 views

Trouble with branch cuts plotting a real function

When I plot the following function ...
Axionlike particles's user avatar
1 vote
2 answers
189 views

Help with the visualization of a function

I am trying to make the plot of an specific function through integration from others, but Wolfram-Alpha and Desmos are having problems with it, so I came here to see if someone could help me using ...
Joako's user avatar
  • 175
2 votes
2 answers
119 views

Construct plot of $exp(1/z)$ [closed]

I want to plot the function $f(z) = e^\frac{1}{z}$ in 3 forms: First to be a plot like [this][1]. But I want to show legend of both magnitude and imaginary part scales. Second to be a plot only with $\...
ProofSeeker's user avatar
5 votes
2 answers
283 views

Blurry shadows of 3D plots and objects

I am using a shadow function, planarShadow, as shared by Prof. Jens Nöckel on Shadows of 3D plots and objects This function works perfectly while making sharp ...
user444's user avatar
  • 2,816
0 votes
0 answers
52 views

Function becomes jagged when being multiplied with a very small prefactor

When I try to scale down a sigmoidal function by multiplying it with a very small value, the function seems to lose its precision, as the curve in the plot becomes jagged lines. The code of the ...
Johnson's user avatar
  • 391
0 votes
1 answer
78 views

How to plot points on a graph curve under logarithmic coordinate axis

I am trying to draw a curve and set a special point based on the logarithmic abscissa, as shown in the following example. The function is 1/(1+(RCw)^2)^0.5. ...
Yao Li's user avatar
  • 111
1 vote
1 answer
89 views

How combine two DensityPlot3D in only one graph

I need to combine two DensityPlot3D in only one graph but the "Show" doesn't work for that. ...
Rubens Filho's user avatar
2 votes
1 answer
75 views

How to make a secondary top frame for a function?

I want to make a plot with two x-axes, one on the bottom and another on the top, where the variables are different but the function is the same. For instance, let f = y(a,b). How can I have in the ...
Jacinto Paulo's user avatar
4 votes
1 answer
87 views

Peak Appearances in Plot Outputs from Optimization Routines

Dear fellow researchers and Mathematica enthusiasts, I've been working on a computational physics problem and encountered an interesting issue regarding the appearance of peaks in my plots, which I ...
Everlin Martins's user avatar
5 votes
2 answers
186 views

Contour Plot - L-Shaped

I am trying to plot a contour with an L-shaped form. I started by illustrating the contour function (horizontal, orange) and adding a line (vertical, black). ...
Tom's user avatar
  • 395
2 votes
1 answer
122 views

Find the Intersection Point of Two Complex Functions Using Complex3DPlot

I want to find the intersection point using ComplexPlot3D. I have a function call it $f(\lambda,k)$ ($k$ is fixed) such that at two particular values of $\lambda_{1,...
ZHENGYAO HUANG's user avatar

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