0
$\begingroup$

I am investigating a sieve theory problem concerning the non-emptiness of sets defined by forbidding two residues modulo each prime in a specific set. The setup is as follows:

  • Let $s$ be a positive integer.
  • Define $R_r$ as the set of primes $q$ satisfying $q \equiv \pm 1 \mod 6$ and $5 \le q \le 6s \pm 1$.
  • Define $R_0 = \{1, 2, \ldots, 3s^2 \pm s\}$.
  • For each prime $q \in R_r$, choose two distinct residues $e_1(q), e_2(q) \mod q$.
  • The sieved set is:
    $$ R_0(e_1, e_2) = \left\{ a \in R_0 : a \not\equiv e_1(q) \text{ or } e_2(q) \pmod{q} \ \forall q \in R_r \right\}. $$ Theorem: There exists a minimal $s_0$ such that for all $s \ge s_0$ and any choice of residues $e_1(q), e_2(q)$, the set $R_0(e_1, e_2)$ is non-empty.

Known Results:

  1. For $s = 7$ (interval length $154$, primes $\{5,7,11,13,17,19,23,29,31,37,41,43\}$), a greedy algorithm (selecting residues that maximize removals) leaves $19$ survivors. Thus, non-emptiness holds.
  2. For $s = 6$ (interval length $114$, primes $\{5,7,11,13,17,19,23,29,31,37\}$), the same greedy algorithm yields 0 survivors, suggesting non-emptiness fails for some residue choices.

Computational Challenges:

  • Exhaustive search for $s = 6$ is infeasible ($\approx 3^{10}$ residue choices).
  • The greedy algorithm minimizes survivors locally, but we seek confirmation that it achieves the global minimum (i.e., whether $0$ is attainable).

Theoretical Lower Bound:
A sequential bound $\mathtt{removals} ≤ ⌈2R/q⌉$ gives $17$ survivors for $s = 6$, but this conflicts with the greedy result ($0$). The discrepancy arises because:
$$ \left\lceil \frac{2R}{q} \right\rceil \leq \min\left(2\left\lceil \frac{R}{q}\right\rceil, R\right) $$
ensures the bound is a safe overestimate of survivors (not a guarantee of non-emptiness).

Questions:

  1. Minimal $s_0$:

    • Is $s = 7$ indeed the minimal $s_0$?
    • For $s = 6$, does there exist any residue choice that removes all integers in $[1, 114]$? If yes, how can such residues be constructed?
  2. Sieve-Theoretic Tools:

    • Are there results (e.g., Brun sieve, Selberg sieve) that provide strict positive lower bounds for $|R_0(e_1, e_2)|$ in this setting?
    • Can existing sieves handle the dependence on residue choices?
  3. Algorithmic Verification:

    • Beyond the greedy heuristic, is there a computationally feasible method to verify the worst-case for $s = 6$?
$\endgroup$

0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.