2
$\begingroup$

Is there a generalized formula for the product of falling factorial polynomials $(x)_n$? From Wikipedia the product of two falling factorials can be expressed as:

\begin{equation} (x)_m (x)_n = \sum\limits_{k=0}^{m}\binom{m}{k}\binom{n}{k}k! \cdot (x)_{m+n-k} \end{equation}

I am wondering if there is a more general formula for $T$ products. I.e. for some integers $\alpha_1, \alpha_2, ... \alpha_T$:

\begin{equation} \prod\limits_{t=1}^{T}(\alpha_t + x - 1)_{\alpha_t} \end{equation}

Is there a concise expression for the coefficients $c_k$ of the polynomial that results:

\begin{equation} \prod\limits_{t=1}^{T}(\alpha_t + x - 1)_{\alpha_t} = \sum\limits_{k=T}^{\sum \alpha_i}c_k x^k \end{equation}

The Wikipedia page referenced "Specializations of MacMahon symmetric functions and the polynomial algebra" but aside from this I haven't found many other references for these types of formulas. Is there a recommended reference book for these types of combinatorial expressions? Thank you!

$\endgroup$
0

1 Answer 1

4
$\begingroup$

I'm not sure if you can get a simple expression, but the product in question can be expressed as $\alpha_1!\cdots\alpha_T!$ times the coefficient of $z_1^{\alpha_1}\cdots z_T^{\alpha_T}$ in $$\left( (1-z_1)\cdots (1-z_T)\right)^{-x}.$$ In terms of elementary symmetric polynomials of $z_i$, $$c_k = \frac{(-1)^k}{k!} \alpha_1!\cdots\alpha_T!\ [z_1^{\alpha_1}\cdots z_T^{\alpha_T}]\ \log(1-e_1+e_2-\dots)^k.$$

$\endgroup$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.