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Questions tagged [amenability]

6 votes
1 answer
249 views

$\DeclareMathOperator\WAP{WAP}$Question: Suppose that $S$ is a discrete cancellative left amenable semigroup and $m$ is a left invariant mean on $\ell^\infty(S)$. When we restrict $m$ to $\WAP(S)$, ...
Sohail Farhangi's user avatar
4 votes
0 answers
200 views

Let $(M,\tau)$ be a tracial von Neumann algebra, and $q \in M$ be a (nonzero) projection, and let $\mathcal H = L^2(M)$ be the standard representation. Using the definition of injectivity ($M \subset ...
pitariver's user avatar
  • 407
1 vote
0 answers
240 views

My hobby is to collect characterizations of amenability of group as many as possible. If the accumulation amounts to 365, then I'm planning to make a day-by-day calendar which deals with one of them ...
2 votes
0 answers
170 views

A discrete group $G$ satisfying Følner condition means that there exists a net $(F_j)_{j\in J}$ of nonempty finite subsets of $G$ such that $\mathop{lim}\limits_{j}\frac{|F_j\triangle gF_j|}{|F_j|}=0$ ...
jack's user avatar
  • 99
4 votes
0 answers
74 views

It is a 33 yrs. old conjecture that amenable Banach algebras that are reflexive as Banach spaces are finite dimensional [1]. To the best of my knowledge, there is no proof of this conjecture in this ...
Onur Oktay's user avatar
  • 2,988
12 votes
2 answers
749 views

Let $G$ be an infinite, discrete, countable group. Can $G$ have a translation-invariant ultrafilter? An ultrafilter $\mathcal{F} \subset 2^G$ is translation-invariant if $A \in \mathcal{F}$ implies $g ...
Vladimir's user avatar
  • 1,332
2 votes
0 answers
135 views

Let $M$ be a von Neumann algebra and $U(M)=\{x\in M: x^*=x^{-1}\}$ be its unitary group. In this post, we equip $U(M)$ only with the relative weak$^*$ topology $\sigma(M,M_*)$. Then, $U(M)$ is a ...
Onur Oktay's user avatar
  • 2,988
3 votes
1 answer
268 views

Let $G$ be a countable amenable group. We consider sequences $(z_g)_{g\in G}$ of complex numbers with $|z_g|=1$ for all $g\in G$. I will say $(z_g)_{g\in G}$ is background noise for a (left-)Følner ...
Saúl RM's user avatar
  • 13.1k
5 votes
0 answers
167 views

This is crossposted from MSE. We say a subset $A$ of a group $G$ is a monotile for $G$ if $G$ is a disjoint union of right translates of $A$. In his article Monotileable Amenable Groups, B. Weiss ...
Saúl RM's user avatar
  • 13.1k
1 vote
0 answers
284 views

By two-sided Følner sequence I mean a sequence $(F_N)_N$ of subsets of $G$ which is both a left-Følner and a right-Følner sequence. Context: I just came up with this question and surprisingly I haven'...
Saúl RM's user avatar
  • 13.1k
0 votes
0 answers
135 views

Let $A$ be a $C^*$-algebra with only finite dimensional irreducible representations. As in a previous question, let $\textrm{w}_0(A)$ denote the subspace of $\ell^{\infty}(A)$ consisting of all weakly ...
Onur Oktay's user avatar
  • 2,988
1 vote
0 answers
147 views

Let $G$ be an infinite compact group and $A=L^1(G)$. It is known that $c_0(A)$ is amenable [Runde2020, p.80] while $\ell^{\infty}(A)$ is not [Daws2009] . Let $\textrm{w}_0(A)$ denote the subspace of $\...
Onur Oktay's user avatar
  • 2,988
3 votes
1 answer
211 views

Let $G$ be a (countable) discrete group and let $X$ be a locally compact Hausdorff space. Assume that $G$ acts on $X$ by homeomorphisms. Recall that the action is (topologically) amenable if there ...
Alcides Buss's user avatar
15 votes
1 answer
1k views

I am interested in the amenability properties of infinite products of solvable groups. The following facts are well-known: Any solvable group is amenable. The class of solvable groups is closed under ...
Asgar's user avatar
  • 153
1 vote
1 answer
243 views

Let $G$ be a discrete nonamenable countable group acting on a standard probability space $(X,\mu)$ through measure-preserving transformations. Is the action of $G$ always amenable? (Amenable action, ...
Ujan Chakraborty's user avatar

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