Skip to main content

Questions tagged [regular-graph]

1 vote
0 answers
85 views

Let $G$ be a 4-regular graph that can be decomposed as a Hamiltonian cycle and triangles. Does it always have a cycle decomposition that is compatible with the cycle plus triangles decomposition? Two ...
gotcha game's user avatar
1 vote
1 answer
145 views

The question concerns complete graphs but for regular polygons. In general, complete graphs are found in graph theory and the definitions do not include metric geometry. However as one can see for ...
Toni Mhax's user avatar
  • 907
2 votes
1 answer
164 views

Prove $G$ is regular if $d(u, v)$ is $x$ for adjacent $u$ and $v$ and is $y \ge 2$ otherwise. Here $d(u, v)$ denotes the number of common adjacent vertices between $u$ and $v$. PS: I've been working ...
Nima Aryan's user avatar
3 votes
1 answer
276 views

Let $X, Y$ be non-empty, disjoint sets and let $R\subseteq X\times Y$ be a binary relation. For $x\in X$, we set $R(x) = \{y\in Y: (x,y) \in R\}$ and for $y\in Y$, let $R^{-1}(y) = \{x\in X:(x,y)\in R\...
Dominic van der Zypen's user avatar
0 votes
0 answers
102 views

I am looking for a reference for the following fact. Let $r\geq 3$ be constant, let $G(n,r-2)$ be a random (simple) $(r-2)$-regular graph and let $H(n)$ be an independent random Hamiltonian cycle (on ...
35T41's user avatar
  • 269
2 votes
2 answers
204 views

Question: what can be said about the existence of $2k$ regular graphs, $1\lt k$ that have a $1$-factor and a $2$-factor? Provided their existence, what is/are the smallest for $k$? The graphs must be ...
Manfred Weis's user avatar
  • 14.3k
1 vote
0 answers
184 views

Let $G_{n,d}$ be $d$-regular random graph. We know that for $d \geq 3$, $G \in G_{n,d}$ a.a.s. has a $1$-factorisation when $n$ is even. So, the resulting graph that obtained from randomly choosing $d$...
Yuhang Bai's user avatar
2 votes
1 answer
562 views

Consider a $k$ regular graph of $n$ vertices, where $3 \leq k \leq (n-1)$. Is there any upper or lower bound, in the worst case, known for either the tree-width or the clique width of each $k$ regular ...
RandomMatrices's user avatar
1 vote
1 answer
245 views

Let $G$ be a symmetric $n$-regular graph. For which $k$ it is possible to delete some vertices from $G$ to obtain $k$-regular graph $G'$? For example, if $G$ is icosahedral graph (i.e. $5$-regular ...
Fedor Nilov's user avatar
5 votes
0 answers
198 views

A Hamiltonian decomposition of a finite simple graph is a partition of its edge set so that each partition class forms a Hamiltonian cycle. This is only possible if the graph is $2k$-regular. ...
M. Winter's user avatar
  • 14.8k
2 votes
1 answer
536 views

The definition of block is Block of $G$ is a maximal subgraph $G'$ of $G$ with no cut vertex of $G'$ itself. Of course, there can exist many blocks in $G$. In particular, isolated vertices, edges in ...
okw1124's user avatar
  • 361
3 votes
0 answers
158 views

I want to prove that ‘If the girth of a $2k$-regular graph $G$ is larger than the diameter of a $k$-edge tree $T$, then $G$ is covered by edge-disjoint copies of $T$.’ I tried several ways to solve ...
okw1124's user avatar
  • 361
2 votes
1 answer
610 views

A graph $G$ is Hamiltonian if there is a Hamiltonian cycle in $G$. Suppose $G$ is a $k$-edge connected $k$-regular graph with $k>1$. Does this ensure that $G$ is Hamiltonian? If not, how about ...
Cyriac Antony's user avatar
5 votes
2 answers
1k views

What is the smallest 3-regular graph to have a unique perfect matching? With a large enough number of nodes, it is possible for a 3-regular graph to have no perfect matching (example can be seen in ...
PickupSticks's user avatar
3 votes
2 answers
630 views

There is a related question on how to generate all regular graphs; however, the procedure is random and repeats the generated graphs. Plus, there is no stop condition, unless recording the total ...
Sergey Ivanov's user avatar

15 30 50 per page