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Questions tagged [schur-functors]

3 votes
1 answer
122 views

Let $V$ be the standard $2g$-dimensional representation of $\mathrm{Sp}(V)$ (with $g \ge 1$), and for each $m \ge 1$ let $S^m V$ denote the $m$-th symmetric power. Consider the Schur functor $S^{(2,1)}...
kindasorta's user avatar
  • 3,416
2 votes
0 answers
86 views

As the title. In general, given a partition or say, a Young diagram $\lambda$ and a linear space $V$ of dimension $n$, we can construct a Schur module corresponding to the irreducible $GL(n)$-...
Dun Liang's user avatar
3 votes
0 answers
152 views

There are two versions of Schur functors. One is defined by Akin, Kaan; Buchsbaum, David A.; Weyman, Jerzy, Schur functors and Schur complexes, Adv. Math. 44, 207-278 (1982). ZBL0497.15020. which ...
Dun Liang's user avatar
7 votes
1 answer
453 views

Let $\lambda$ be a partition, $S_\lambda$ the Schur functor attached to $\lambda$, and let $p_\lambda(t)$ be the polynomial determined by the condition that $\dim S_\lambda(k^n) = p_\lambda(n)$ for ...
Noah Snyder's user avatar
  • 28.7k
2 votes
0 answers
163 views

Let $\mathcal{E}$ be a vector bundle of rank $r$ and degree $d$ over some smooth projective variety $X$. Furthermore, let $\lambda$ be a partition of $n$. We apply the $\lambda$-th Schur functor to $\...
Max Briest's user avatar
1 vote
0 answers
157 views

It has been cited in several places (eg. https://arxiv.org/pdf/1912.05519.pdf) that the S-module Ass is isomorphic to the composite of the S-modules Com and Lie. Is there a reference which gives the ...
ani's user avatar
  • 101
4 votes
0 answers
250 views

For partition $\mu$ let $\mathbb{S}^{\mu}V = V^{\otimes \mu} \cdot c_{\mu}$, where $c_{\mu}$ is the Young symmetrizer. I'm trying to prove that $\mathbb{S}^{\nu / \lambda}V$ is the polynomial part of $...
NicStr's user avatar
  • 59
6 votes
1 answer
529 views

Let $\mathcal{C}$ and $\mathcal{D}$ be categories and let $T : \mathcal{C} \rightarrow \mathcal{D}$ be a functor. Suppose that $F : \mathcal{D}^\mathrm{op} \rightarrow \mathrm{Set}$ is a functor. (So ...
Mark Wildon's user avatar
  • 12.2k
2 votes
0 answers
99 views

I've seen hints at the following result: Let $M$ be a 3-dimensional manifold and let $T := T^*M$ be the cotangent bundle. By Schur-Weyl Duality, the 3rd tensor product can be written as follows: $$T^...
Rdrr's user avatar
  • 941
3 votes
0 answers
271 views

I want to compute $$ S^{2,2,\dots,2,1}(\mathbb C^{2m-1} \otimes W)^{SL(2m-1)} $$ Here $m$ numbers should appear in the superscipt of the Schur functor, and the last superscript means to take $SL(2m-1)$...
Drew's user avatar
  • 1,559
7 votes
0 answers
3k views

In the representation theory, if $S^{\lambda}(V)$ is the irreductible representation of $\text{GL}(V)$ associated to a partition $\lambda \vdash n$ (in perticular, $S^n(V)$ is the $n^{\text{th}}$ ...
eti902's user avatar
  • 941
6 votes
0 answers
150 views

Let $V$ be a finite dimensional representation of symmetric group $\mathbb{S}_n.$ Consider a natural map $$\pi \colon \Lambda^2 V \otimes \Lambda^2 V \longrightarrow \Lambda^4 V.$$ Let $[\Lambda^2 V]...
Daniil Rudenko's user avatar
2 votes
0 answers
303 views

I am trying to understand the Schur functor $S^{(2,1)}$. Let's try on a vector space $V$ of dimension 3. The general definition is : $S^{\lambda}V = V^{\otimes n} \otimes_{S_n} V^{\lambda}$ where $V^...
eti902's user avatar
  • 941
5 votes
0 answers
1k views

In the paper Henning Krause, Koszul, Ringel, and Serre duality for strict polynomial functors, arXiv:1203.0311v4, Krause defines something that he calls an "internal tensor product" on the category of ...
darij grinberg's user avatar
4 votes
0 answers
872 views

Question 1 (short version). Let $R$ be a commutative ring with unity. Let $F$ and $G$ be two $R$-modules. Let $n\in\mathbb{N}$. Is it true that the $n$-th symmetric power $\operatorname*{Sym}\...
darij grinberg's user avatar

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