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I would like to see all questions whose tags contain the word "geometry".

Question. Is there a simple way to do that on MathOverflow (different from manually checking all 36 tags containing the word "geometry")?

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  • $\begingroup$ Learning a bit of SQL and using the Data Explorer is probably the way to go. $\endgroup$ Commented Oct 2, 2025 at 9:32

2 Answers 2

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You can search for [*geometry*], the wildcards will make the query automatically expand into the (apparently) 20 most popular tags following that pattern.

screenshot of search results page

This Data Explorer query suggests there are some 700 questions missing from the search results, I hope a 2% error is acceptable. And manually checking the other is probably just a matter of searching for [alexandrov-geometry] or [conformal-geometry] or ..., though you'll get a lot of duplicates with the link above for questions which have multiple geometry tags.

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I will just add some comment and links to accompany Glorfindel's answer.

First, here are some SEDE queries to find such questions. You can change the parameters to use other string than "geometry" and to choose how many questions to return. (Although they will probably time out with a large limit on the number of results.)

We can also look at the tags containing the word geometry:

One can also manually create a search link for all geometry tags. And also a similar search with some keyword. The search strings could be manually edited further - depending on which tags are interesting for the OP. Naturally, this reflects the tags which exists at the moment - this might change in the future. So the search for [*geometry*] suggested by Glorfindel has the advantage that it will be updated if new tags are added.


1In the case of there are good reasons why the tag should not be merged - the deprecated tags on this site have not been cleaned up. See, for example, What to do with the synonyms for the deprecated tags? and some of the discussions linked there. Disagreement with the synonym for was raised by domotorp in this answer.

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