std::divides
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< cpp | utility | functional
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Definido no cabeçalho <functional>
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template< class T > struct divides; |
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Objeto de função para executar divisão. Efetivamente chama operator/ em duas instâncias de
T
tipo.Original:
Function object for performing division. Effectively calls operator/ on two instances of type
T
.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Índice |
[editar] Tipos de membro
Tipo
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
result_type
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T
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first_argument_type
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T
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second_argument_type
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T
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[editar] Funções de membro
operator() |
devolve o resultado da divisão do primeiro argumento pelo segundo argumento Original: returns the result of the division of the first argument by the second argument The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função pública membro) |
std :: divide ::Original:std::divides::The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.operator()
Original:
std::divides::
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
T operator()( const T& lhs, const T& rhs ) const; |
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Returns the result of division of lhs
by rhs
.
Parameters
lhs, rhs | - | Os valores para dividir um a outro
Original: values to divide one by other The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Return value
The result of lhs / rhs.
Exceptions
(none)
Possible implementation
T operator()(const T &lhs, const T &rhs) const { return lhs / rhs; } |