Python add a string to all set's elements

Question

I'm wondering what is the Python way to perform the following - Given a set :

s = {'s1','s2','s3'}

I would like to perform something like :

s.addToAll('!')

to get

{'s1!','s2!','s3!'}

Thanks!

Tuples are immutable. See: stackoverflow.com/questions/626759/… — Alvin K.
– Alvin K., Commented Apr 12, 2013 at 5:49

jamylak · Accepted Answer · 2013-04-12 05:41:48Z

7

For an actual set:

>>> s = {'s1','s2','s3'}
>>> {x + '!' for x in s}
set(['s1!', 's2!', 's3!'])

That method is 2.7+, If you are using Python 2.6 you would have to do this instead:

>>> s = set(['s1','s2','s3'])
>>> set(x + '!' for x in s)
set(['s1!', 's2!', 's3!'])

edited Apr 12, 2013 at 5:41

answered Apr 12, 2013 at 5:36

jamylak

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7 Comments

Grijesh Chauhan Over a year ago

nice but I feel he need for tuple your previous answer [x + '!' for x in s]

Stjepan Bakrac Over a year ago

@GrijeshChauhan That would result in a list, need to tuple() it still.

jamylak Over a year ago

@GrijeshChauhan I decided to answer the actual question which says sets, it is kind ambiguous so that's why I said "for an actual set"

jamylak Over a year ago

@GrijeshChauhan Or just tuple(x + '!' for x in s), submit that if you want, it could be the answer

jamylak Over a year ago

@GrijeshChauhan The tuple constructor accepts an iterable to create a new tuple from it. That works with a list, tuple([x + '!' for x in s]), as you have shown. In Python if you remove the square brackets in a function call it uses a generator expression instead, which evaluates it's items lazily.

|

Priyesh Solanki · Accepted Answer · 2013-04-12 06:18:05Z

0

You can try this:

>>> s = ['s1','s2','s3']
>>> list(i + '!' for i in s)

answered Apr 12, 2013 at 6:18

Priyesh Solanki

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1 Comment

jamylak Over a year ago

Check the updated question, this is now wrong. Also you should always use [i + '!' for i in s] list comps instead of list constructor

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