I want to exclude some result if it contains a word of an list of words(array)
For example:
$result = 'http://www.facebook.com/plugins/likebox.php';
$discardKeys = array('chat', 'facebook', 'twitter');
Like this way:
if (strpos($result,$discardKeys)==false) {
echo $result;
}
You could use a regex:
$result = 'http://www.facebook.com/plugins/likebox.php';
$discardKeys = array('chat', 'facebook', 'twitter');
$discardKeys = array_map('preg_quote', $discardKeys);
if (preg_match('/'.implode('|', $discardKeys).'/', $result, $matches)) {
//..
}
preg_quote, but you should use () for regex delimiters - otherwise you'd need to escape slashes which makes the whole preg_quote function much less tidy (you'd need to pass an extra argument)By the way I post this another but longer solution:
function istheRight($url, $discardKeys){
foreach ($discardKeys as $key) {
if (strpos($url, $key) == true) {return false;}
}
return true;
}
So in the example:
$result = 'http://www.facebook.com/plugins/likebox.php';
$discardKeys = array('chat', 'facebook', 'twitter');
if (isTheRight($result, $discardKeys)) {echo $result;}
And here is this shorter answer using str_replace to check is $result changes :
$result = 'http://www.facebook.com/plugins/likebox.php';
$discardKeys = array('chat', 'facebook', 'twitter');
if ($result == str_replace($discardKeys, "", $result)) {echo $result;}