How to convert this PHP array into a JavaScript array?

Question

What would this PHP array look like in JavaScript?

What would be the closest translation?

$nursery_rhyme = array(“mary”, “had”, “a”, “little”, “lamb”);

This is not even valid PHP (there are no smart quotes in PHP). Wild guess: copied from your homework? — Tomalak
– Tomalak, Commented Dec 18, 2010 at 17:21

scoates · Accepted Answer · 2010-12-18 17:30:15Z

5

As others mentioned, the curly/smart quotes are invalid.

You can get the JavaScript representation of most simple PHP structures by running the data through json_encode():

php> echo json_encode(array("mary", "had", "a", "little", "lamb"))
["mary","had","a","little","lamb"]

answered Dec 18, 2010 at 17:30

scoates

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István Ujj-Mészáros · Accepted Answer · 2010-12-18 17:21:11Z

3

var nursery_rhyme=new Array("mary", "had", "a", "little", "lamb");

answered Dec 18, 2010 at 17:21

István Ujj-Mészáros

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Eric · Accepted Answer · 2010-12-18 17:30:39Z

1

var nursery_rhyme = ["mary", "had", "a", "little", "lamb"];

answered Dec 18, 2010 at 17:30

Eric

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Jonathan · Accepted Answer · 2010-12-18 17:33:12Z

1

var nursery_ryhme = ["mary", "had", "a", "little", "lamb"];

edited Dec 18, 2010 at 17:33

answered Dec 18, 2010 at 17:21

Jonathan

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2 Comments

Tomalak Over a year ago

There are no smart quotes in JavaScript. ;-)

Jonathan Over a year ago

Haha true. I apparently fail at copy+paste. I wonder if I should even bother fixing the answer, because off all the other 100% equivalent answers.

pts · Accepted Answer · 2010-12-18 17:42:30Z

0

Closest JS translation:

$nursery_rhyme = new Array("mary", "had", "a", "little", "lamb");

Notice:

no var is needed
you can still use the $

edited Dec 18, 2010 at 17:42

pts

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answered Dec 18, 2010 at 17:37

vol7ron

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