How to remove lines of file content, if has specific trailing string? [duplicate]

Question

There is a file with this simple content:

projectA-app1
projectA-app2
projectA-app-mobile
projectB-app1

Now I need to get every application name into one line (removing line breaks)

apps=$(cat file.txt| tr -s '\n' ' ')

but I also need to remove all applications, which are ending with -mobile. How do I do that?

The result of this example should be

projectA-app1 projectA-app2 projectB-app1

Or grep -v "-mobile$" file.txt|xargs Look for xargs about merging lines — F. Hauri - Give Up GitHub
– F. Hauri - Give Up GitHub, Commented Jul 15, 2024 at 12:51

0stone0 · Accepted Answer · 2024-07-15 12:48:11Z

1

You could reverse grep on mobile$ and then pass the result to tr:

grep -v -E 'mobile$' bla | tr -s '\n' ' '

You could also combine these 2 into a signle awk command:

awk '!/mobile$/ { printf "%s ", $0 } END { print "" }' bla

projectA-app1 projectA-app2 projectB-app1

answered Jul 15, 2024 at 12:48

0stone0

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