I am trying to sum certain numbers in a column using awk. I would like to sum just column 3 of the "smiths" to get a total of 212. I can sum the whole column using awk but not just the "smiths". I have:
awk 'BEGIN {FS = "|"} ; {sum+=$3} END {print sum}' filename.txt
Also I am using putty. Thank you for any help.
smiths|Login|2
olivert|Login|10
denniss|Payroll|100
smiths|Time|200
smiths|Logout|10
awk -F '|' '$1 ~ /smiths/ {sum += $3} END {print sum}' inputfilename
-F flag sets the field separator; I put it in single quotes because it is a special shell character. $1 ~ /smiths/ applies the following {code block} only to lines where the first field matches the regex /smiths/. Note that since you're not really using a regex here, just a specific value, you could just as easily use:
awk -F '|' '$1 == "smiths" {sum += $3} END {print sum}' inputfilename
Which checks string equality. This is equivalent to using the regex /^smiths$/, as mentioned in another answer, which includes the ^ anchor to only match the start of the string (the start of field 1) and the $ anchor to only match the end of the string. Not sure how familiar you are with regexes. They are very powerful, but for this case you could use a string equality check just as easily.
unzip -lv /appl/tmp/data.lar | grep documentlibrary | awk '{sum += $1} END {print sum/1024/1024}'
Another approach is to use awk associative arrays, more info here. This line produces the desired output:
awk -F '|' '{a[$1] += $3} END{print a["smiths"]}' filename.txt
As a side effect, the array stores all other values:
awk -F '|' '{a[$1] += $3} END{for (i in a) print i, a[i]}' filename.txt
Output:
smiths 212
denniss 100
olivert 10
Very good so far. All you need to do is add a selector before the block to add the sum. Here we check that the first argument contains only "smiths":
awk 'BEGIN {FS = "|"} ; $1 ~ /^smiths$/ {sum+=$3} END {print sum}'
You could shorten this a bit by specifying the field separator as an option. In awk it's generally a good idea to initialize variables on the command line:
awk -F'|' '$1 ~ /^smiths$/ {sum+=$3} END {print sum}'
I personally would prefer to keep the awk section as simple as possible and do as much as you can without it. Comingled logic doesn't take advantage of the power of Unix pipelines and is thus harder to understand, debug or modify for closely related use cases.
cat filename.txt | perl -pe 's{.*|}{}g' | awk '{sum+=$1} END {print sum}'
cat filename.txt | grep smiths | awk -F '|' '{sum+=$NF} END {print sum}'
-F option to specify separator.$NF is for "last column".
cat and grep are unnecessary here.
/smiths/{...} if the grep call is not there. This is a trivial modification, but it provides significant benefits: decreases the number of running processes, simplifies the error control, and makes the code clearer.
Using Raku (formerly known as Perl_6)
...summing values in a hash, returning all:
~$ raku -ne 'BEGIN my %h;
.split("|") andthen %h{.[0]} += .[2];
END .put for %h.sort;' file
Sample Input:
smiths|Login|2
olivert|Login|10
denniss|Payroll|100
smiths|Time|200
smiths|Logout|10
Sample Output (1):
denniss 100
olivert 10
smiths 212
Above is an answer written in Raku, a member of the Perl-family of programming languages. Raku is called at the command line with -ne non-autoprinting, linewise flags.
BEGIN by declaring a %h hash.| pipe, and .[0] the first column is added as key to the %h hash, with .[2] the third column summed-in as value.END, above the complete hash is sorted and returned.So how to return the value for smiths, specifically? Simply substitute the final statement like so:
END .put for %h<smiths>;
Sample Output (2): 212
