Bash Array Contains false positives

Question

I'm trying to see if a value exists in a bash array. If so, do something. Else, do something else.

I can't figure out why this is always failing for me.

Basically start with two separate values, concatenate them with a delimiter, search against an array and if that entire string (delimiter and all) is in any of the array elements do something, else do something else.

#!/bin/bash

FNAME="JACK"
LNAME="BLACK"

SEARCHNAME=()
SEARCHNAME+="JACK-BLACK"
SEARCHNAME+="JOHN-JAMES"
SEARCHNAME+="CHRIS-TOPHER"
SEARCHNAME+="JEN-NAY"

NAME="${FNAME}-${LNAME}"

if [[ $NAME == *"${SEARCHNAME[@]}"* ]]; then
    echo "PASSED"
else
    echo "FAILED"
fi

echo "SEARCH IN: ${SEARCHNAME[@]}"
echo "FOR NAME: ${NAME}"

Results:

FAILED
SEARCH IN: JACK-BLACKJOHN-JAMESCHRIS-TOPHERJEN-NAY
FOR NAME: JACK-BLACK

I've also tried if [[ "${NAME}" == *"${SEARCHNAME[@]}"* ]] but no difference... I'm missing something pretty obvious here and am thinking it might be with the way I'm declaring my array? I'd expect the lack of space between each array element (seen in array output) to not make a difference because of the wild-card characters?

Answer 1

Correct the array assignments, and change the test to a regex.

#!/bin/bash

FNAME="JACK"
LNAME="BLACK"

SEARCHNAME=()
SEARCHNAME+=("JACK-BLACK")
SEARCHNAME+=("JOHN-JAMES")
SEARCHNAME+=("CHRIS-TOPHER")
SEARCHNAME+=("JEN-NAY")

NAME="${FNAME}-${LNAME}"

if [[ "${SEARCHNAME[@]}" =~ $NAME ]]; then
    echo "PASSED"
else
    echo "FAILED"
fi

echo "SEARCH IN: ${SEARCHNAME[@]}"
echo "FOR NAME: ${NAME}"

Answer 2

There are a couple things to note here:

1. Using the == in place of =~ as we"re not looking for equality here.
2. Since this is a regex not wildcard so ...

3. The order of operands in the [[ needs to be reversed, viz., like as:

   if [[ ${SEARCHNAME[@]} =~ .*$NAME.* ]]