Renaming file name with shell script

Question

I have lots of file name like below;

KO.ADVT..HHE.D.2017.163.121959.SAC
KO.ADVT..HHN.D.2017.163.121957.SAC
KO.ADVT..HHZ.D.2017.163.121959.SAC
KO.ARMT..HHE.D.2017.163.121957.SAC
KO.ARMT..HHN.D.2017.163.121957.SAC
KO.ARMT..HHZ.D.2017.163.121956.SAC
KO.BGKT..HHE.D.2017.163.121958.SAC
KO.BGKT..HHN.D.2017.163.121959.SAC
KO.BGKT..HHZ.D.2017.163.121954.SAC
KO.BRGA..HNE.D.2017.163.121955.SAC
KO.BRGA..HNN.D.2017.163.121959.SAC
KO.BRGA..HNZ.D.2017.163.121959.SAC
KO.BUYA..HNE.D.2017.163.121954.SAC
KO.BUYA..HNN.D.2017.163.121955.SAC
KO.BUYA..HNZ.D.2017.163.121956.SAC
KO.CAVI..HHE.D.2017.163.121958.SAC
KO.CAVI..HHN.D.2017.163.121958.SAC
KO.CAVI..HHZ.D.2017.163.122001.SAC
KO.CRLT..HHE.D.2017.163.121958.SAC
KO.CRLT..HHN.D.2017.163.121959.SAC
KO.CRLT..HHZ.D.2017.163.121958.SAC
KO.CTYL..HHE.D.2017.163.122000.SAC
KO.CTYL..HHN.D.2017.163.121959.SAC
KO.CTYL..HHZ.D.2017.163.122004.SAC
KO.DST..HNE.D.2017.163.121959.SAC
KO.DST..HNN.D.2017.163.121957.SAC
KO.DST..HNZ.D.2017.163.121956.SAC
KO.EDRB..HHE.D.2017.163.121959.SAC
KO.EDRB..HHN.D.2017.163.121955.SAC
KO.EDRB..HHZ.D.2017.163.121958.SAC

and I want to change their name like this

ADVT.HHE.KO
ADVT.HHN.KO
ADVT.HHZ.KO
ARMT.HHE.KO
ARMT.HHN.KO
ARMT.HHZ.KO
BGKT.HHE.KO
BGKT.HHN.KO
BGKT.HHZ.KO
BRGA.HNE.KO
BRGA.HNN.KO
BRGA.HNZ.KO
BUYA.HNE.KO
BUYA.HNN.KO
BUYA.HNZ.KO
CAVI.HHE.KO
CAVI.HHN.KO
CAVI.HHZ.KO
CRLT.HHE.KO
CRLT.HHN.KO
CRLT.HHZ.KO
CTYL.HHE.KO
CTYL.HHN.KO
CTYL.HHZ.KO
DST.HNE.KO
DST.HNN.KO
DST.HNZ.KO
EDRB.HHE.KO
EDRB.HHN.KO
EDRB.HHZ.KO

I used this code

 for file in *.SAC
    do
        newfilename="${file:3:6}${file:7:9}"
    echo mv $file $newfilename
    done

but the result like this;

ADVT....HHE.D.2
ADVT....HHN.D.2
ADVT....HHZ.D.2
DST..H.HNE.D.20
DST..H.HNN.D.20
DST..H.HNZ.D.20
.... so on.

How can I get new files names with my code ?

Thanks in advance.

Answer 1

With perl rename:

rename -n 's/^(.*?)\.(.*?)\.\.(.*?)\..*/$2.$3.$1/' *SAC

Remove -n switch if the output looks good.

.*? is like .* but not greedy

Answer 2

Using bash and awk:

for f in *SAC; do
    echo mv "$f" "$(awk -F. -v OFS=. '{print $2, $4, $1}' <<< "$f")"
done

Remove echo statement if the output looks good