0

I'm trying to read 5 analog inputs, but all the pins are reading the same as pin A0, plus or minus a couple points. I tried using pulldown resistors on all 5 pins and it made no difference. The board is a Leonardo. Thanks for any ideas/help!

void setup() {
    Serial.begin(115200);
    analogReference(EXTERNAL);
}

void loop() {
    int A0, A1,A2,A3,A4;
    delay(200);
    A0= analogRead(A0);
    A1= analogRead(A1);
    A2= analogRead(A2);
    A3= analogRead(A3);
    A4= analogRead(A4);

    Serial.print(A0);
    Serial.print(" ");
    Serial.print(A1);
    Serial.print(" ");
    Serial.print(A2);
    Serial.print(" ");
    Serial.print(A3);
    Serial.print(" ");
    Serial.print(A4);
    Serial.print("\n");
}

1 Answer 1

6
int A0, A1,A2,A3,A4;
delay(200);
A0= analogRead(A0);
A1= analogRead(A1);
A2= analogRead(A2);
A3= analogRead(A3);
A4= analogRead(A4);

Your local variables (A0 through A4) are shadowing the global variables for the pins (A0 through A4). Give your local variables different names.

1
  • 1
    Thank you! I knew it must be something stupid I'd overlooked. Commented Jun 8, 2015 at 17:05

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.