std::return_temporary_buffer
Aus cppreference.com
![]() |
This page has been machine-translated from the English version of the wiki using Google Translate.
The translation may contain errors and awkward wording. Hover over text to see the original version. You can help to fix errors and improve the translation. For instructions click here. |
definiert in Header <memory>
|
||
template< class T > void return_temporary_buffer( T* p ) |
||
Speicher freigibt zuvor mit std::get_temporary_buffer zugeordnet .
Original:
Deallocates storage previously allocated with std::get_temporary_buffer.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Inhaltsverzeichnis |
[Bearbeiten] Parameter
p | - | der Zeiger zuvor durch std::get_temporary_buffer zurückgegeben
Original: the pointer previously returned by std::get_temporary_buffer The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[Bearbeiten] Rückgabewert
(None)
Original:
(none)
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[Bearbeiten] Beispiel
#include <algorithm> #include <iostream> #include <memory> #include <string> int main() { const std::string s[] = {"string", "1", "test", "..."}; std::string* p = std::get_temporary_buffer<std::string>(4).first; std::copy(std::begin(s), std::end(s), std::raw_storage_iterator<std::string*, std::string>(p)); for (std::string* i = p; i != p+4; ++i) { std::cout << *i << '\n'; i->~basic_string<char>(); } std::return_temporary_buffer(p); }
Output:
string 1 test ...
[Bearbeiten] Siehe auch
gibt nicht initialisierten, temporären Speicher für die angegebene Zahl von Elementen zurück (Funktions-Template) |