std::remove_pointer
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definiert in Header <type_traits>
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template< class T > struct remove_pointer; |
(seit C++11) | |
Provides the member typedef type
which is the type pointed to by T
, or, if T
is not a pointer, then type
is the same as T
.
Inhaltsverzeichnis |
[Bearbeiten] Mitglied Typen
Name
Original: Name The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
type
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the type pointed to by T or T if it's not a pointer
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[Bearbeiten] Mögliche Implementierung
template< class T > struct remove_pointer {typedef T type;}; template< class T > struct remove_pointer<T*> {typedef T type;}; template< class T > struct remove_pointer<T* const> {typedef T type;}; template< class T > struct remove_pointer<T* volatile> {typedef T type;}; template< class T > struct remove_pointer<T* const volatile> {typedef T type;}; |
[Bearbeiten] Beispiel
This section is incomplete Reason: no example |
[Bearbeiten] Siehe auch
(C++11) |
prüft, ob ein Typ ist ein Zeiger-Typ Original: checks if a type is a pointer type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (Klassen-Template) |
(C++11) |
fügt Zeiger auf den angegebenen Typ Original: adds pointer to the given type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (Klassen-Template) |