877

How do I pass a function as a parameter without the function executing in the "parent" function or using eval()? (Since I've read that it's insecure.)

I have this:

addContact(entityId, refreshContactList());

It works, but the problem is that refreshContactList fires when the function is called, rather than when it's used in the function.

I could get around it using eval(), but it's not the best practice, according to what I've read. How can I pass a function as a parameter in JavaScript?

0

16 Answers 16

1203

You just need to remove the parenthesis:

addContact(entityId, refreshContactList);

This then passes the function without executing it first.

Here is an example:

function addContact(id, refreshCallback) {
    refreshCallback();
    // You can also pass arguments if you need to
    // refreshCallback(id);
}

function refreshContactList() {
    alert('Hello World');
}

addContact(1, refreshContactList);

11
  • 8
    Based on the question, the callback doesn't accept parameters, which is why I have left them out of the example. I'll add a comment about it.
    – Fenton
    Commented Nov 8, 2012 at 9:42
  • 1
    How would it look like to pass an anonymous function instead of a pre-defined one ?
    – Veverke
    Commented Oct 21, 2014 at 13:49
  • 6
    @Veverke It would look like this... addContact(1, function(id) { console.log(id); });
    – Fenton
    Commented Nov 24, 2014 at 10:46
  • 1
    The class syntax in ECMAScript wouldn't have an = sign... class myFuncs { rather than class myFuncs = {. You'd also need to be running in an environment that supported the class syntax (not all browsers support it yet). If you are still struggling, it might be better suited to a whole new question as your problem isn't about passing functions - it is general ES syntax.
    – Fenton
    Commented Jun 21, 2016 at 21:08
  • 1
    How calling this App.ThisFunction("show") function on another? for example: myotherfunction("arg1",App.ThisFunction("show")); and myotherfunction is ---> myotherfunction('arg1',func){ func; } HOW??????????????????????
    – Mostafa
    Commented Aug 8, 2018 at 8:38
558

If you want to pass a function, just reference it by name without the parentheses:

function foo(x) {
    alert(x);
}
function bar(func) {
    func("Hello World!");
}

//alerts "Hello World!"
bar(foo);

But sometimes you might want to pass a function with arguments included, but not have it called until the callback is invoked. To do this, when calling it, just wrap it in an anonymous function, like this:

function foo(x) {
   alert(x);
}
function bar(func) {
   func();
}

//alerts "Hello World!" (from within bar AFTER being passed)
bar(function(){ foo("Hello World!") });

If you prefer, you could also use the apply function and have a third parameter that is an array of the arguments, like such:

function eat(food1, food2) {
    alert("I like to eat " + food1 + " and " + food2 );
}
function myFunc(callback, args) {
    //do stuff
    //...
    //execute callback when finished
    callback.apply(this, args);
}

//alerts "I like to eat pickles and peanut butter"
myFunc(eat, ["pickles", "peanut butter"]); 

5
  • 115
    this should be ranked higher as he also addresses how to pass a function with arguments
    – deltanine
    Commented Aug 27, 2014 at 3:16
  • 5
    And something I will add to this is that this feature alone - being able to pass JavaScript functions as arguments or variables or the like - is the feature that makes JavaScript so powerful and so great to code in.
    – TheHans255
    Commented Dec 9, 2015 at 22:16
  • @Compynerd255 I agree, this and the ability to quickly create object literals are my two favorite aspects of Javascript. I always miss object literals in languages that don't have them.
    – dallin
    Commented Dec 10, 2015 at 22:34
  • 6
    For the "wrap it in an anonymous function" example, in case it is not obvious, the anonymous function return the function itself (with parameters) and it is invoked when it reaches the parenthesis in func(). This took me a while to figure out, so I thought it might help others.
    – hubpixel
    Commented Apr 26, 2019 at 1:07
  • @dallin in your first example, what is the role of 'func' parameter, it would be better if you describe whats exactly happening in that code because it seems quite unusual approach as i did'nt see any in built function like 'func('Hello World'). Thanks in Advance! Commented Oct 26, 2023 at 5:03
61

Example 1:

funct("z", function (x) { return x; });

function funct(a, foo){
    foo(a) // this will return a
}

Example 2:

function foodemo(value){
    return 'hello '+value;
}

function funct(a, foo){
    alert(foo(a));
}

//call funct    
funct('world!',foodemo); //=> 'hello world!'

look at this

1
  • at first example you should add return keyword, like this: function funct(a, foo){ return foo(a) // this will return a } otherwise you will get undefined Commented May 20, 2020 at 22:08
44

To pass the function as parameter, simply remove the brackets!

function ToBeCalled(){
  alert("I was called");
}

function iNeedParameter( paramFunc) {
   //it is a good idea to check if the parameter is actually not null
   //and that it is a function
   if (paramFunc && (typeof paramFunc == "function")) {
      paramFunc();   
   }
}

//this calls iNeedParameter and sends the other function to it
iNeedParameter(ToBeCalled); 

The idea behind this is that a function is quite similar to a variable. Instead of writing

function ToBeCalled() { /* something */ }

you might as well write

var ToBeCalledVariable = function () { /* something */ }

There are minor differences between the two, but anyway - both of them are valid ways to define a function. Now, if you define a function and explicitly assign it to a variable, it seems quite logical, that you can pass it as parameter to another function, and you don't need brackets:

anotherFunction(ToBeCalledVariable);
1
  • 2
    Just typeof paramFunc == "function" is enough, cause if it isn't callable, then you can ignore it. Commented Mar 10, 2015 at 14:26
20

There is a phrase amongst JavaScript programmers: "Eval is Evil" so try to avoid it at all costs!

In addition to Steve Fenton's answer, you can also pass functions directly.

function addContact(entity, refreshFn) {
    refreshFn();
}

function callAddContact() {
    addContact("entity", function() { DoThis(); });
}
12

I chopped all my hair off with that issue. I couldn't make the examples above working, so I ended like :

function foo(blabla){
    var func = new Function(blabla);
    func();
}
// to call it, I just pass the js function I wanted as a string in the new one...
foo("alert('test')");

And that's working like a charm ... for what I needed at least. Hope it might help some.

0
9

I suggest to put the parameters in an array, and then split them up using the .apply() function. So now we can easily pass a function with lots of parameters and execute it in a simple way.

function addContact(parameters, refreshCallback) {
    refreshCallback.apply(this, parameters);
}

function refreshContactList(int, int, string) {
    alert(int + int);
    console.log(string);
}

addContact([1,2,"str"], refreshContactList); //parameters should be putted in an array
0
6

You can also use eval() to do the same thing.

//A function to call
function needToBeCalled(p1, p2)
{
    alert(p1+"="+p2);
}

//A function where needToBeCalled passed as an argument with necessary params
//Here params is comma separated string
function callAnotherFunction(aFunction, params)
{
    eval(aFunction + "("+params+")");
}

//A function Call
callAnotherFunction("needToBeCalled", "10,20");

That's it. I was also looking for this solution and tried solutions provided in other answers but finally got it work from above example.

1
  • Before using eval() in production code research the security implications. Many devs simply avoid it, myself included. eval === evil is my mnemonic. Commented Sep 17, 2021 at 15:18
3

Here it's another approach :

function a(first,second)    
{        
return (second)(first);           
}     

a('Hello',function(e){alert(e+ ' world!');}); //=> Hello world     
3

In fact, seems like a bit complicated, is not.

get method as a parameter:

 function JS_method(_callBack) { 

           _callBack("called");  

        }

You can give as a parameter method:

    JS_method(function (d) {
           //Finally this will work.
           alert(d)
    });
1
  • 1
    Please, explain your answer. Commented Oct 14, 2014 at 10:16
3

The other answers do an excellent job describing what's going on, but one important "gotcha" is to make sure that whatever you pass through is indeed a reference to a function.

For instance, if you pass through a string instead of a function you'll get an error:

function function1(my_function_parameter){
    my_function_parameter();   
}

function function2(){
 alert('Hello world');   
}

function1(function2); //This will work

function1("function2"); //This breaks!

See JsFiddle

1

Some time when you need to deal with event handler so need to pass event too as an argument , most of the modern library like react, angular might need this.

I need to override OnSubmit function(function from third party library) with some custom validation on reactjs and I passed the function and event both like below

ORIGINALLY

    <button className="img-submit" type="button"  onClick=
 {onSubmit}>Upload Image</button>

MADE A NEW FUNCTION upload and called passed onSubmit and event as arguments

<button className="img-submit" type="button"  onClick={this.upload.bind(this,event,onSubmit)}>Upload Image</button>

upload(event,fn){
  //custom codes are done here
  fn(event);
}
1

By using ES6:


const invoke = (callback) => {
  callback()
}


invoke(()=>{
  console.log("Hello World");
})
0

If you can pass your whole function as string, this code may help you.

convertToFunc( "runThis('Micheal')" )

function convertToFunc( str) {    
  new Function( str )()
 } 
function runThis( name ){
    console.log("Hello", name) // prints Hello Micheal
 }

0
// Go through this code and try to understand what I have done.
var hello=(name)=>
{
    console.log("Hello",name);
}
let loadScript =(src,callback,name )=>
{
let script = document.createElement('script');
script.src=src;

script.onload = function()
{
    console.log("Script Loaded");
}
document.body.appendChild(script);
setTimeout(function()
{
    callback(name);
    // console.log("hii");
},2000);
}
setTimeout(`loadScript("https://cdn.jsdelivr.net/npm/es-module-shims@1/dist/es-module-shims.min.js",hello,"Gaurav")`,5000);
1
  • 1
    Your answer could be improved with additional supporting information. Please edit to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers in the help center.
    – Community Bot
    Commented Mar 21, 2023 at 9:52
-2

You can use a JSON as well to store and send JS functions.

Check the following:

var myJSON = 
{
    "myFunc1" : function (){
        alert("a");
    }, 
    "myFunc2" : function (functionParameter){
        functionParameter();
    }
}



function main(){
    myJSON.myFunc2(myJSON.myFunc1);
}

This will print 'a'.

The following has the same effect with the above:

var myFunc1 = function (){
    alert('a');
}

var myFunc2 = function (functionParameter){
    functionParameter();
}

function main(){
    myFunc2(myFunc1);
}

Which is also has the same effect with the following:

function myFunc1(){
    alert('a');
}


function myFunc2 (functionParameter){
    functionParameter();
}

function main(){
    myFunc2(myFunc1);
}

And a object paradigm using Class as object prototype:

function Class(){
    this.myFunc1 =  function(msg){
        alert(msg);
    }

    this.myFunc2 = function(callBackParameter){
        callBackParameter('message');
    }
}


function main(){    
    var myClass = new Class();  
    myClass.myFunc2(myClass.myFunc1);
}
1
  • 9
    Your top code example is not JSON. This is a standard JavaScript Object. You also cannot send/receive functions in JSON. Commented Jan 31, 2014 at 12:03

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