I need to loop a section of HTML code with php/javascript, suggestions?

Question

I've attempted using a for loop and heredoc in php using similar code:

 $options = ''; 

for($Year = date("Y"); $Year <= date("Y") + 5; $Year++) 
{ $options .= "<option>$Year</option>\n"; } 

$Select = <<<QQxQQ 
<select> 
$options 
</select> 
QQxQQ; 


print "$Select";

But no luck...

EDIT These examples are great, thanks guys. This is what I'm trying to iterate

<li><a href="#"><span>$looped</span></a></li>

Where $looped is a value of a fetched mysql column. As you can probably see, I'm trying to iterate an element of a list x amount of times (where x = number of rows of sql query).

I thought trying to put the results into an array and then cycling through the array, however I still couldn't get the HTML code to go through the parser accordingly without being considered a string.

The interpreter is complaining about a whitespace after your heredoc declaration, otherwise it's fine - test — Emissary
– Emissary, Commented Apr 27, 2013 at 10:40
Based on the update you posted, try this then Echoing mysqli queries — Tigger
– Tigger, Commented Apr 27, 2013 at 11:29

jeyraof · Accepted Answer · 2013-04-27 10:39:12Z

4

How about this?

<select>
<?php
    for($Year = date("Y"); $Year <= date("Y") + 5; $Year++) {
        echo "<option>".$Year."</option>";
    }
?>
</select>

answered Apr 27, 2013 at 10:39

jeyraof

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Tigger · Accepted Answer · 2013-04-27 10:41:40Z

0

You could try something like this:

<?php

$year = date('Y');
$end = ($year + 5);
do {
    $option .= '<option>'.$year.'</option>';
} while (++$year <= $end);

echo '<select>'.$option.'</select>';

?>

answered Apr 27, 2013 at 10:41

Tigger

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half-fast · Accepted Answer · 2013-04-27 10:42:00Z

0

Heredocs have their place, but imo they are overrated and often used in the wrong context.

Try this:

$year = date("Y");
for( $Year = $year; $Year <= ($year+5); $Year++ ) { 
    $options .= "<option value=\"$Year\">$Year</option>\n"; 
}

echo "<select name='years' id='years'>";
echo $options;
echo "</select>";

answered Apr 27, 2013 at 10:42

half-fast

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Amir · Accepted Answer · 2013-04-27 10:49:32Z

0

<select>
<?php
for($Year = date("Y"); $Year <= date("Y") + 5; $Year++) 
{ echo "<option>$Year</option>\n"; } 
?>
</select>

answered Apr 27, 2013 at 10:49

Amir

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