Exclude elements of one array from another array

Question

I need to exclude elements of the array $tempobjects from the array $objects. What is the quickest way to do this?

$objects = new MyObjects();
$tempobjects = new MyObjects();

for($i=0; $i<10; $i++) {
  $objects->addObject(new MyObject(...));
}

//...fill $tempobjects with some temporary data

$tempobjects = $objects - $tempobjects; // HOW TO DO SOMETHING LIKE THIS?

Looks like $objects and $tempObjects are objects (or objects that comprise a collection of data) rather than arrays — Mark Baker
– Mark Baker, Commented May 16, 2013 at 16:04
array_diff or array_diff_assoc are the usual ways to do this for arrays, but as mark baker said, you have objects, so those functions probably won't work. try converting your objects to arrays. — user428517
– user428517, Commented May 16, 2013 at 16:06
Possible duplicate of PHP: remove duplicate items in an array — Anigel
– Anigel, Commented May 16, 2013 at 16:06
@sgroves do you know if it would work if both of the objects in question implemented the ArrayAccess Interface? — Orangepill
– Orangepill, Commented May 16, 2013 at 16:07
@Anigel, in this case is not an array... Maybe he will need to add a method on the class that does this for him. — Henrique Barcelos
– Henrique Barcelos, Commented May 16, 2013 at 16:07

gkalpak · Accepted Answer · 2013-05-16 16:21:45Z

2

If $tempobjects and $objects were arrays (like your title mentions), which based on your sample code they are not, you could exclude elements using functions array_diff() (for comparing values) or array_diff_key() (for comparing keys).

See, also, this short demo.

answered May 16, 2013 at 16:21

gkalpak

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