bash shell script 101 - loop in a script

Question

I am trying to create a script that automates one line of command which is used for archiving selected files to tape and creating a text file with the archived files. a and b are inputs and in the example below and I define them as 03 and 15.

a=03

b=15

tar -cvf /dev/tapedrive file_03 file_04 file_05 .........file_15 > /text_files/backup_file_03-15.txt

the script I came up with is below,

#! /bin/bash

a=03
b=15

for (( c=$a; c<=$b; c++ ))
$tt=" ";
do
    if[ ! $c $a ]
    then
        $c="0$c"
    fi
    $tt .= " file_".$c.""
end    

echo tar -cvf /dev/tapedrive $tt > /text_files/backup_file_$a-$b.txt

done

it's 'echo' for now instead of 'do' to make sure I get the right final command line. I am receiving the error

jag5v1.sh: line 9: syntax error near unexpected token `$tt=" "'
jag5v1.sh: line 9: `$tt=" ";'

I would appreciate any input. Thanks!

devnull · Accepted Answer · 2013-11-12 06:57:15Z

2

It seems that all you need to say is:

a=03
b=15
echo tar -cvf /dev/tapedrive $(seq -f 'file_%02g' $a $b) > /text_files/backup_file_$a-$b.txt

answered Nov 12, 2013 at 6:57

devnull

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1 Comment

Hussain Over a year ago

This is more elegant.

Hussain · Accepted Answer · 2013-11-12 07:19:36Z

1

I have corrected your code. Try this -

#! /bin/bash
a=3
b=15
tt=' ';

for c in $(seq $a $b);
do
    if [ $c -le 9 ]
    then
    c="0"$c
    fi
    tt=$tt" file_"$c
done
echo tar -cvf /dev/tapedrive $tt > /text_files/backup_file_0$a-$b.txt

edited Nov 12, 2013 at 7:19

answered Nov 12, 2013 at 7:04

Hussain

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